Reputation: 11
I have a problem with the button3 it's the UPDATE BUTTON, The message box keeps saying it's a syntax error in the UPDATE Statement. And also if I create another listbox, if I insert a new data, it does not make me insert another data in the 2nd listbox. So if I insert something on the 1st listbox, that index would, for example, be 9, then I would try to insert on the next listbox, but then it would proceed to the index 10.
OleDbCommand cmd = new OleDbCommand();
OleDbConnection cn = new OleDbConnection();
OleDbDataReader dr;
private void listBox2_Click(object sender, EventArgs e)
{
ListBox l = sender as ListBox;
if (l.SelectedIndex != 1)
{
listBox1.SelectedIndex = l.SelectedIndex;
listBox2.SelectedIndex = l.SelectedIndex;
textBox2.Text = listBox2.SelectedItem.ToString();
}
}
private void button1_Click(object sender, EventArgs e)
{
if (textBox1.Text != "")
{
string q = "insert into Table1 (name) values ('"+textBox1.Text.ToString()+"')";
doSomething(q);
textBox1.Text = null;
}
}
private void button2_Click(object sender, EventArgs e)
{
if (listBox1.SelectedIndex != -1)
{
string q = "delete from Table1 where id=" + listBox1.SelectedItem.ToString();
doSomething(q);
}
}
private void button3_Click(object sender, EventArgs e)
{
if (textBox2.Text != "" & listBox1.SelectedIndex != -1)
{
string q = "update Table1 set (name) '" + textBox2.Text.ToString() + "' where id " + listBox1.SelectedItem.ToString();
doSomething(q);
textBox2.Text = "";
}
}
private void doSomething(String q)
{
try
{
cn.Open();
cmd.CommandText = q;
cmd.ExecuteNonQuery();
cn.Close();
loaddata();
}
catch (Exception e)
{
cn.Close();
MessageBox.Show(e.Message.ToString());
}
}
Upvotes: 1
Views: 138
Reputation: 8839
string q = "update Table1 set (name) '" + textBox2.Text.ToString() + "' where id " + listBox1.SelectedItem.ToString();
In the above code (btn3) your are missing id =
Write code like this :
string q = "update Table1 set (name) '" + textBox2.Text.ToString() + "' where id=" + listBox1.SelectedItem.ToString();
UPDATE :
My Access query function:
public void ExecuteAccessQuery(string _pQuery)
{
OleDbConnection con = new OleDbConnection("DatabaseConnectionString");
OleDbCommand cmd = new OleDbCommand(_pQuery, con);
if (con.State == System.Data.ConnectionState.Closed)
{
con.Open();
}
cmd.ExecuteNonQuery();
con.Close();
}
Upvotes: 0
Reputation: 26209
Problem 1: you are missing =
Symbol while providing input parameters.
Try This:
string q = "update Table1 set [name]= '" + textBox2.Text.ToString() + "' where id= " + listBox1.SelectedItem.ToString();
Problem 2: you are not assigning connection object to `OleDbCommand.
Add This: before executing command
cmd.Connection=cn;
Complete Code:
OleDbCommand cmd = new OleDbCommand();
OleDbConnection cn = new OleDbConnection();
OleDbDataReader dr;
private void listBox2_Click(object sender, EventArgs e)
{
ListBox l = sender as ListBox;
if(l.SelectedIndex!=-1)
textBox2.Text = l.SelectedItem.ToString();
}
}
private void button1_Click(object sender, EventArgs e)
{
if (textBox1.Text != "")
{
string q = "insert into Table1(name) values ('"+textBox1.Text.ToString()+"')";
doSomething(q);
textBox1.Text = null;
}
}
private void button2_Click(object sender, EventArgs e)
{
if (listBox1.SelectedIndex != -1)
{
string q = "delete from Table1 where id=" + listBox1.SelectedItem.ToString();
doSomething(q);
}
}
private void button3_Click(object sender, EventArgs e)
{
if (textBox2.Text != "" & listBox1.SelectedIndex != -1)
{
string q = "update Table1 set [name] ='" + textBox2.Text.ToString() + "' where id =" + listBox1.SelectedItem.ToString();
doSomething(q);
textBox2.Text = "";
}
}
private void doSomething(String q)
{
try
{
cn.Open();
cmd.CommandText = q;
cmd.Connection=cn;
cmd.ExecuteNonQuery();
cn.Close();
loaddata();
}
catch (Exception e)
{
cn.Close();
MessageBox.Show(e.Message.ToString());
}
}
Suggestion : your query is open to SQL injection attacks
, i would suggest to use Parameterised Queries
to avoid them.
Using Parameterised Queries :
private void doSomething(String q)
{
try
{
cn.Open();
cmd.CommandText = "update Table1 set [name]=@name where id=@id";
cmd.Parameters.AddWithValue("@name",textBox2.Text.ToString());
cmd.Parameters.AddWithValue("@id",listBox1.SelectedItem.ToString());
cmd.ExecuteNonQuery();
cn.Close();
loaddata();
}
catch (Exception e)
{
cn.Close();
MessageBox.Show(e.Message.ToString());
}
}
Upvotes: 1