Reputation: 8433
I have the following directory structure (relevant bits only):
app
- build
- script.js
- js
- lib
- require.js
- jquery-1.10.2.js
- app.js
- index.html
Gruntfile.js
module.exports = function (grunt) {
var gruntConfig = {
pkg: grunt.file.readJSON('package.json'),
requirejs: {
compile: {
options: {
name: 'app',
baseUrl: 'app/assets/js',
out: 'app/assets/build/script.js',
include: ['lib/require'],
uglify: {
// beautify: true,
defines: {
DEBUG: ['name', 'false']
}
},
paths: {
jquery: "lib/jquery-1.10.2"
}
}
}
},
};
grunt.initConfig(gruntConfig);
grunt.loadNpmTasks('grunt-contrib-requirejs');
};
require(['jquery'], function ($) {
// Do stuff
});
How do I set it up so that it copies all the JavaScript needed into build/script.js, not just app.js and require.js when I tell it to (erroring when I try to use jQuery)? I also want to be able to add modules without adding them to my Gruntfile, just by adding them to script.js.
Upvotes: 4
Views: 8730
Reputation: 327
Try adding this to your options object:
findNestedDependencies: true
This way grunt-contrib-requirejs (actually just requirejs) will find whatever dependencies are listed on your config file.
Hope it works for you.
Upvotes: 0
Reputation: 106
You can have a mainConfigFile defined and inside config file have paths to you lib code like this
Contents of gruntfile:
requirejs: {
compile: {
options: {
baseUrl: "app/js/",
mainConfigFile: app/config.js",
out: "build/script.js",
name: "config"
}
}
}
Contents of config file:
require.config({
paths: {
lib: "<path to>/js/lib",
jquery: "<path to>/js/lib/jquery-1.10.2.min",
.
and particular file required
.
}
Requirejs will add the contents of all path files to the optimized code.
Upvotes: 1