CODEWITHSUNDEEP
phpfunction
Mariano
Mariano

Reputation: 221

Use external included file inside php functions

I'm writing a functions.php file...now, some functions must access the db. I have a db_connect.php file which contains the connection script. I've included it in functions.php with:

require "sys/db_connect.php";

but how to use the connection script ($con) inside

function a() {
   ...
}
function c() {
   ...
}

and so on? I've tried already setting $con variable as global, but no success.

Upvotes: 2

Views: 743

Answers (5)

Ali
Ali

Reputation: 3461

There are three ways to do this, either accessing the value using $GLOBALS, declaring it as a global variable or passing it as a parameter

1st way:

include 'db_connect.php';
    function a() {
        $link = $GLOBALS['con'];
        // you can assign $GLOBALS['con'] or use it as a normal variable
    }

2nd way:

include 'db_connect.php';
function a() {
    global $con;
    // then use it as a normal variable
 }

3rd way:

function a($con) {
    // use the variable
}

Read more about variable scopes here

Upvotes: 1

bao7uo
bao7uo

Reputation: 101

If you have assigned a variable $con in db_connect.php outside any functions as follows:

//----------
//sys/db_connect.php
//----------
$con = 'my connection script'; //You don't need to put global here

Then you can use $con in functions a() and c() in another php file as follows:

//----------
//other_file.php
//----------
require 'sys/db_connect.php';

function a(){
 global $con;   //global allows $con from above to be used in this function a()

 print_r($con); //This line just for testing purposes!
}

function b(){
 global $con;   //global allows $con to be used in this function b()

 print_r($con); //This line just for testing purposes!
}

Upvotes: 0

StackSlave
StackSlave

Reputation: 10617

I do this:

// sys/db_connect.php
<?php
function db(){
  return new mysqli('host', 'username', 'password', 'database');
}
?>

// functions.php
<?php
require 'sys/db_connect.php';
/* you can even close the connection and reopen it this way
   $db = db(); $db->close(); $database = db(); */
function a() {
  $db = db();
}
function c() {
  $db = db();
}
?>

Upvotes: 0

user1864610
user1864610

Reputation:

This structure should work. Note where the global declarations appear. I'd normally pass the $con variable into the function as an argument rather than using it as a global, though.

dbconnect.php

<?
$con = mysqli_connect("blah","blah","blah","blah");
?>

functions.php

require('dbconnect.php');
function a() {
  global $con;
   ...
}
function c() {
  global $con;
   ...
}

Upvotes: 0

AbraCadaver
AbraCadaver

Reputation: 79024

function a($db) {
   //do something with $db
}
function c($db) {
   //do something with $db
}

$result = a($conn);
$something = c($conn);

Upvotes: 2

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