Reputation: 1757
Using angular, I want to submit a form and store the response. My code looks something like this:
<form ng-controller="myController" action="myAction" method="POST">
<input type="text" name="name" />
<input type="submit" ng-click="submit" />
</form>
<script>
function myController($scope, $http) {
$scope.submit = function() {
$http.post(url, data).success(function(data) {
$scope.result = data;
});
}
}
</script>
How do I get url
and data
to be the form action and inputs, respectively? I don't want to send JSON, I want the server side to see this is a regular HTML form submit.
Upvotes: 3
Views: 212
Reputation: 1757
Thank, @Vincent Ramdhanie, for pointing me in the right direction. Here's what I ultimately did, using plenty of jQuery thrown in:
function myController($scope, $http) {
$('form').submit(function() {
return false;
});
$scope.submit = function() {
form = $('form');
data = form.serialize();
url = form.attr('action')
$http.post(url, data,
{ headers:
{ 'Content-Type': 'application/x-www-form-urlencoded; charset=UTF-8'}
}).success(function(data) {
$scope.result = data;
}
);
}
}
Upvotes: 4
Reputation: 103145
This is how I accomplish this, start by binding the form data to your model, Then use a transform to transform your JSON data into regular post parameters. This solution depends on the jQuery param() function:
<form ng-controller="myController" method="POST">
<input type="text" name="name" ng-model="name"/>
<input type="submit" ng-click="submit" />
</form>
function myController($scope, $http) {
$scope.name = "";
/* Helper function to transform the form post to a regular post rather than JSON */
var transform = function(data) {
return $.param(data);
}
$scope.submit = function() {
$http.post('myAction', $scope.name, {
headers: { 'Content-Type': 'application/x-www-form-urlencoded; charset=UTF-8'},
transformRequest: transform
})
.success(function (data) {
$scope.result = data;
});
}
}
Upvotes: 3