CODEWITHSUNDEEP
phparraysarray-push
Bas
Bas

Reputation: 33

Append keys to existing array value

I have the following array and by using array_push & I am getting not the right result.

Array:

Array
(
    [0] => 1039
    [1] => 417
    [2] => 418
)

Array Push:

array_push($array, array("a","b","c"));

Result:

Array
(
    [0] => 1039
    [1] => 417
    [2] => 418
    [3] => Array
    (
        [0] => a
        [1] => b
        [2] => c
    )

)

I want the a,b,c append to value 417 for example .

Disirable result:

Array
(
    [1039] => 1039
    [417] => Array
    (
        [0] => a
        [1] => b
        [2] => c
    )
    [418] => 418

)

How can this be done?

SOLUTION:

$data = Array (
    0 => 1039,
    1 => 417,
    2 => 418,
 );

foreach( $data as $key => $val ) {
    $new_data[$val] = 0;
}

foreach( $new_data as $k => $v ){
    if( $k == 417 ){
        $new_data[$k] = array( 'p' => 50, 'pp' => 75 );
    }
}
print_r($new_data);

Upvotes: 3

Views: 199

Answers (6)

zai
zai

Reputation: 75

use loop to display new array data

 $data = Array (
      0 => 1039,
      1 => 417,
      2 => 418,
      );

 foreach( $data as $key => $val ) {
     if ( $val == 417 ) {
         $val = array( 'a','b','c' );
     }

     $new_data = array( $key => $val );
     foreach( $new_data as $key2 => $val2 ) {
         if ( is_array( $val2 ) ) {
             $val2 = array( 417 => $val );
         }
         $new_data1 = array( $key2 => $val2 );

    print_r($new_data1);
    }
}

Upvotes: 0

Barmar
Barmar

Reputation: 780724

It doesn't really make sense, but this will do what you show in your example:

$array[1] .= print_r(array("a","b","c"), true);

.= does string concatenation, and passing true as the second argument to print_r makes it return the string that it would have printed.

The result of this is that $array[1] is a string that begins with 417 and is followed by the printed representation of the added array. There's no actual array in there. I'm not sure what you plan to do with this, but it matches your example.

Upvotes: 1

Linga
Linga

Reputation: 10555

Use array_splice

array_splice($your_arrray, 1, 0, array("a","b","c"));

Upvotes: 0

Vitalii
Vitalii

Reputation: 161

My running php code:

$arr = array(0=>1039,1=>417,2=>418);
array_push($arr, array("a","b","c"));
var_dump($arr);

And var_dump($arr)

array(4) { [0]=> int(1039) [1]=> int(417) [2]=> int(418) [3]=> array(3) { [0]=> string(1) "a" [1]=> string(1) "b" [2]=> string(1) "c" } }

Upvotes: 0

Giacomo1968
Giacomo1968

Reputation: 26056

Just do it like this & all should work as expected:

array_push($array, "a", "b", "c");

The array_push manual page explains it best:

$stack = array("orange", "banana");
array_push($stack, "apple", "raspberry");
print_r($stack);

But if the values you are adding are in an array already, then perhaps use array_merge instead:

array_merge($array, array("a","b","c"));

Upvotes: 0

Zarathuztra
Zarathuztra

Reputation: 3251

Don't use array push in this case (granted I might be missing your question)

$arr = array(1,2,3);
$arr[1] = array('a','b','c');
//would output your above example.

Upvotes: 0

Related Questions