CODEWITHSUNDEEP
pythonbyteoutput
Sravan K Ghantasala
Sravan K Ghantasala

Reputation: 1318

escaping the leading 'b' in python

I was trying to strip a string like 

var/vob/bxxxxx/xxxxx/vob

I am doing it like...

'var/vob/bxxxxx/xxxxx/vob'.lstrip('/var/vob/')

I am expecting an output like ...

bxxxxx/xxxx/vob

But it is only giving... 

xxxx/xxxxxx/vob

Yes I know because of the first letter is b and in python prefix b for a string stands for converting it into bytes, and I have read this too...

But what I wanted to know is how to bypass this thing.. I want to get the desired output...

I would love to say the things I have tried.. but I don't find any way around to try... can some one throw some light on this...

Thanks :)

Upvotes: 0

Views: 617

Answers (3)

thefourtheye
thefourtheye

Reputation: 239443

The best way to do this would be, like this

data, text = "/var/vob/bxxxxx/IT_test/vob", "/var/vob/"
if data.startswith(text): data = data[len(text):]
print data

Output

bxxxxxx/IT_test/vob

Upvotes: 2

bigblind
bigblind

Reputation: 12867

What about

if s.startswith("var/vob/):
    s = s[8:]

And yes, Mark is right, lstrip removes any haracters from contained in the argument from the string.

Upvotes: 2

Mark Ransom
Mark Ransom

Reputation: 308091

You misunderstand what lstrip does. It removes all characters that are part of the parameter string. Order doesn't matter. Since b is in the string it is removed from the front of the result.

Upvotes: 6

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