CODEWITHSUNDEEP
javaandroidjson
user3082271
user3082271

Reputation: 127

Android JSON Parsing And Conversion

Good morning.

I am trying to parse JSON data into a string but I think I'm doing something wrong: here is the section.

private void read_JSON()
    {
    String JSON;
        JSONObject jso3 = new JSONObject(JSON);
        for (int i=0; i < jso3.length(); i++)
        {

        try
        {

            String name = jso3.getString("Nombre");
            String surname = jso3.getString("Apellidos");
            String date = jso3.getString("Año_nacimiento");
            String child_names = jso3.getString("Nombres_Hijos");


        }catch (JSONException e)
        {
            e.printStackTrace();
        }

        }
    jso3.toString(JSON);    
    }

I created the JSON within the MainActivity.java, it's not on a separate file.

Here is the code of the JSON creation:

private void create_JSON()
{
    JSONObject jso = new JSONObject();

    try {
        jso.put("Nombre","Miguel");
        jso.put("Apellidos", "Garcia");
        jso.put("Año_nacimiento", 1990);
        JSONArray jsa = new JSONArray();
        jsa.put("Blur");
        jsa.put("Clur");
        jso.put("Nombres_Hijos", jsa);

    } catch (JSONException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
    jso.toString();

I have no doubts that the JSON is correctly created, I just need help in understanding how do I parse it and convert it into a String.

I would be very grateful if you could point out to me the flaws in my programming.

Mauro.

Upvotes: 1

Views: 969

Answers (6)

Sachin Shelke
Sachin Shelke

Reputation: 449

Use the following options while parsing JSON to avoid common error.

JSONObject jso3 = new JSONObject(output);
String name = jso3.optString("Nombre",""); // here default value is blank ("")
String surname = jso3.optString("Apellidos",null);// here default value is null
int date = jso3.getInt("Año_nacimiento",0); // here default value is ZERO (0)
JSONArray menuObject = jso3.getJSONArray("Nombres_Hijos");
for(int i=0;i<menuObject.length;i++){   
System.out.println(menuObject.getString(i));
}

Using opt option you can set default return value. Event if that tag not available in JSON data you will get default value.

This works for me better than GSON lib.

Upvotes: 2

Nambi
Nambi

Reputation: 12042

try{   

 String JSON ;
        JSONObject jso3 = new JSONObject(JSON);
        JSONArray menuObject = new JSONArray(jObject.getString("array_inside_json"));   
        for(int i=0;i<menuObject.length;i++){   
        name=jObject.getString("inside"));          


        }

}catch(Exception e){

}

refer this link for more info

Upvotes: 1

Hariharan
Hariharan

Reputation: 24853

Try this..

Your response like below 

{                             ==> JSONObject
    "Año_nacimiento": 1990,   ==> String from JSONObject
    "Nombres_Hijos": [        ==> JSONArray 
        "Blur",               ==> Directly from JSONArray
        "Clur"
    ],
    "Apellidos": "Garcia",
    "Nombre": "Miguel"
}

To parse the JSON use below code:

JSONObject jso3 = new JSONObject(output);
String name = jso3.getString("Nombre");
String surname = jso3.getString("Apellidos");
int date = jso3.getInt("Año_nacimiento");
JSONArray menuObject = jso3.getJSONArray("Nombres_Hijos");
for(int i=0;i<menuObject.length;i++){   
   System.out.println(menuObject.getString(i));
}

Upvotes: 2

dipali
dipali

Reputation: 11188

private void read_JSON(String json)
    {

       JSONObject jObject= new JSONObject(json);
        JSONArray jso3= new JSONArray(jObject.getString("Nombres_Hijos"));   


        for (int i=0; i < jso3.length(); i++)
        {

        try
        {

            String name = jso3.getString("Nombre");
            String surname = jso3.getString("Apellidos");
            String date = jso3.getString("Año_nacimiento");
            String child_names = jso3.getString("Nombres_Hijos");


        }catch (JSONException e)
        {
            e.printStackTrace();
        }

        }
    jso3.toString(JSON);    
    }

Upvotes: 1

alxio
alxio

Reputation: 128

First at all, you seem to ignore Strings created in read_JSON, but i assume you do this to avoid pasting here too much code.

Problem is this line:

 String child_names = jso3.getString("Nombres_Hijos");

Because fields Nombres_Hijos is JsonArray, not String. To read it use:

JSONArray jsa = jso3.getJSONArray("Nombres_Hijos");

Now all depands what you need to do later with this data. Easiest case would be:

String names = jsa.toString(); //["Blur","Clur"]

Upvotes: 1

ravi
ravi

Reputation: 2782

Try this.

String apellidos = jso.getString("Apellidos");
System.out.println(apellidos);

int str2 = jso.getInt("Año_nacimiento");
System.out.println(str2);

String nombre = jso.getString("Nombre");
System.out.println(nombre);

JSONArray array = jso.getJSONArray("Nombres_Hijos");
for(int i = 0; i < array.length(); i++){
    System.out.println(array.get(i));
}

Upvotes: 1

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