CODEWITHSUNDEEP
c++arraysfunctionpointersstructure
user3123327
user3123327

Reputation: 13

Structures and functions(passing by reference)

Please guide me on this code, I want to store list of 5 data using array and function, this is a piece of code of mine, but this is giving me an error ("33"):

Cannot convert `ABC (*)[5]' to `ABC*' for argument `1' to `void pass(ABC*)'

Code:

#include <iostream>

using namespace std;

struct ABC{
   char name[20];
   int phone;
   char address[20];


   };

   void pass(ABC *abc){

  for(int i=0; i<5;i++){
        cout<<"Enter name"<<endl;
        cin>>abc[i].name;

        cout<<"Enter phone"<<endl;
        cin>>abc[i].phone;

        cout<<"Enter address"<<endl;
        cin>>abc[i].address;           

        }

 }

 int main()
 {
ABC abc[5];

   pass(&abc);    

system("PAUSE");
return EXIT_SUCCESS;
}

Upvotes: 0

Views: 79

Answers (2)

Raxvan
Raxvan

Reputation: 6505

You can use pass(&abc[0]); or pass(abc); to get a pointer to the first element in the array. Otherwise if you use &abc alone you get a pointer to a whole array[5] not the elements inside the array.

Upvotes: 5

benipalj
benipalj

Reputation: 704

Arrays are not pointers. But they can decay to pointers when you are doing function calls. So you can pass your array like this:

pass(abc);

Upvotes: 3

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