Reputation: 357
I have two tables.
Tab1:
+------------+
| id | title |
+------------+
| 1 | B |
| 2 | C |
| 3 | A |
| 4 | A |
| 5 | A |
| 6 | A |
| ... |
+------------+
Tab2:
+-------------------------------------------+
| id | item_id | item_key | item_value |
+-------------------------------------------+
| 1 | 1 | value | $4 |
| 2 | 1 | url | http://h.com/ |
| 3 | 2 | value | $5 |
| 4 | 3 | url | http://i.com/ |
| 5 | 3 | value | $1 |
| 6 | 3 | url | http://y.com/ |
| 7 | 4 | value | $2 |
| 8 | 4 | url | http://z.com/ |
| 9 | 5 | value | $1 |
| 10 | 5 | url | http://123.com/ |
| ... |
+-------------------------------------------+
How do I make it so I get a table of ids from Tab1 in order according to criteria from both tables. The criteria are the following:
The resulting table with the ordered results would be:
+------------+
| id | title |
+------------+
| 4 | A |
| 5 | A |
| 3 | A |
| 6 | A |
| 1 | B |
| 2 | C |
| ... |
+------------+
The results should include items that don't have the one, both, or none of the fields from Tab2 set.
Upvotes: 2
Views: 2990
Reputation: 180887
As far as I understand, a simple join will do it. You'll have to join Tab2
twice, since you want to order by values from both rows.
SELECT Tab1.id, Tab1.title
FROM Tab1
JOIN Tab2 t2_val ON t2_val.item_id = Tab1.id AND t2_val.item_key='value'
JOIN Tab2 t2_url ON t2_url.item_id = Tab1.id AND t2_url.item_key='url'
ORDER BY title,
t2_val.item_value DESC,
t2_url.item_value LIKE '%123.com%' DESC
Upvotes: 3
Reputation: 1269503
A little complicated, because when you do the join
you will get multiple rows. Here is an approach that aggregates tab2
before doing the join:
select t1.*
from Tab1 t1 left outer join
(select id,
max(case when item_key = 'value' then item_value end) as value,
max(case when item_key = 'url' then item_value end) as url
from Tab2 t2
group by id
) t2
on t1.id = t2.id
order by t1.title, t2.value desc,
(t2.url like '%123.com%') desc;
Upvotes: 2