CODEWITHSUNDEEP
php
user3072327
user3072327

Reputation: 31

Undefined offset 1, array in php

I have this code in JavaScript:

$.ajax({
    type: "POST",
    url: "funcoes/a-php/ler/ler_config.php",
    data: 'data_id=fish/config/horse/config/car',
    cache: false,
    success: function(data_o){
        alert(data_o);
    }
});

and on the file 'ler_config.php' I have this codes:

if($_SERVER['REQUEST_METHOD'] == 'POST'){
    $data = $_POST['data_id'];
    list($name, $value) = explode('=', $data, 2);
    $result = explode('/config/', $value);
    print_r($result);
}

So I'm having trouble with this line:

list($name, $value) = explode('=', $data, 2);

and php notice me this messanger:

Undefined offset 1

So how can I fix it?

Upvotes: 0

Views: 307

Answers (2)

nl-x
nl-x

Reputation: 11832

This is your post data: data_id=fish/config/horse/config/car
That means that $_POST['data_id'] will already contain fish/config/horse/config/car

Since there is no = in it, exploding it will yield an array with only ONE value with index 0. There will be no second value with index 1. Thus your message about the index not existing.

So in stead of list($name, $value) = explode('=', $data, 2);
... you should do:

$name = 'data_id'; // this is the key value you already used for $data
$value = $_POST['data_id']; // or $value = $data; it's the same

Upvotes: 0

scrowler
scrowler

Reputation: 24406

The problem is that your explode function is splitting $data by = signs (which don't exist in the string) - some basic debugging would have told you that.

This is the format of your string:

data: 'data_id=fish/config/horse/config/car'

... so $_POST['data_id'] = 'fish/config/horse/config/car';

Now, I'm not sure what you're trying to achieve with this code, but if you're trying to split that string from AJAX by the = sign, you just don't need to. It's just telling ajax that data_id is going to be equal to .... The = doesn't actually come out in PHP.

If you're splitting that string, it should be by / instead.

Also, to be clearer with your AJAX, you should wrap your data variables inside {} brackets and not include the variable name inside the quotes:

data: {
    data_id: 'fish/config/horse/config/car'
}

Upvotes: 2

Related Questions