Reputation: 2641
I have created a page called functioncalling.php
that contains two buttons, Submit and Insert.
I want to test which function is executed when a button gets clicked. I want the output to appear on the same page. So, I created two functions, one for each button.
<form action="functioncalling.php">
<input type="text" name="txt" />
<input type="submit" name="insert" value="insert" onclick="insert()" />
<input type="submit" name="select" value="select" onclick="select()" />
</form>
<?php
function select(){
echo "The select function is called.";
}
function insert(){
echo "The insert function is called.";
}
?>
The problem here is that I don't get any output after any of the buttons are clicked.
Where exactly am I going wrong?
Upvotes: 191
Views: 1396869
Reputation: 362
Calling a PHP function using the HTML button: Create an HTML form document which contains the HTML button. When the button is clicked the method POST is called. The POST method describes how to send data to the server. After clicking the button, the array_key_exists()
function called.
<?php
if(array_key_exists('button1', $_POST)) {
button1();
}
else if(array_key_exists('button2', $_POST)) {
button2();
}
function button1() {
echo "This is Button1 that is selected";
}
function button2() {
echo "This is Button2 that is selected";
}
?>
<form method="post">
<input type="submit" name="button1" class="button" value="Button1" />
<input type="submit" name="button2" class="button" value="Button2" />
</form>
source: geeksforgeeks.org
Upvotes: 3
Reputation: 557
You can simply do this. In php, you can determine button click by use of
if(isset($_Post['button_tag_name']){
echo "Button Clicked";
}
Therefore you should modify you code as follows:
<?php
if(isset($_Post['select']){
echo "select button clicked and select method should be executed";
}
if(isset($_Post['insert']){
echo "insert button clicked and insert method should be executed";
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html>
<body>
<form action="functioncalling.php">
<input type="text" name="txt" />
<input type="submit" name="insert" value="insert" onclick="insert()" />
<input type="submit" name="select" value="select" onclick="select()" />
</form>
<script>
//This will be processed on the client side
function insert(){
window.alert("You click insert button");
}
function select(){
window.alert("You click insert button");
}
</script>
</body>
</html>
Upvotes: 2
Reputation: 3682
You cannot call PHP functions like clicking on a button from HTML. Because HTML is on the client side while PHP runs server side.
Either you need to use some Ajax or do it like as in the code snippet below.
<?php
if ($_GET) {
if (isset($_GET['insert'])) {
insert();
} elseif (isset($_GET['select'])) {
select();
}
}
function select()
{
echo "The select function is called.";
}
function insert()
{
echo "The insert function is called.";
}
?>
You have to post your form data and then check for appropriate button that is clicked.
Upvotes: 20
Reputation: 468
I was stuck in this and I solved it with a hidden field:
<form method="post" action="test.php">
<input type="hidden" name="ID" value"">
</form>
In value
you can add whatever you want to add.
In test.php you can retrieve the value through $_Post[ID]
.
Upvotes: 5
Reputation: 109
You can write like this in JavaScript or jQuery Ajax and call the file
$('#btn').click(function(){
$.ajax({
url:'test.php?call=true',
type:'GET',
success:function(data){
body.append(data);
}
});
})
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.0.1/jquery.min.js"></script>
<form method='get' >
<input type="button" id="btn" value="click">
</form>
<?php
if(isset($_GET['call'])){
function anyfunction(){
echo "added";
// Your funtion code
}
}
?>
Upvotes: 8
Reputation: 141
To show $message in your input:
<?php
if(isset($_POST['insert'])){
$message= "The insert function is called.";
}
if(isset($_POST['select'])){
$message="The select function is called.";
}
?>
<form method="post">
<input type="text" name="txt" value="<?php if(isset($message)){ echo $message;}?>" >
<input type="submit" name="insert" value="insert">
<input type="submit" name="select" value="select" >
</form>
To use functioncalling.php as an external file you have to include it somehow in your HTML document.
Upvotes: 14
Reputation: 7776
Yes, you need Ajax here. Please refer to the code below for more details.
Change your markup like this
<input type="submit" class="button" name="insert" value="insert" />
<input type="submit" class="button" name="select" value="select" />
jQuery:
$(document).ready(function(){
$('.button').click(function(){
var clickBtnValue = $(this).val();
var ajaxurl = 'ajax.php',
data = {'action': clickBtnValue};
$.post(ajaxurl, data, function (response) {
// Response div goes here.
alert("action performed successfully");
});
});
});
In ajax.php
<?php
if (isset($_POST['action'])) {
switch ($_POST['action']) {
case 'insert':
insert();
break;
case 'select':
select();
break;
}
}
function select() {
echo "The select function is called.";
exit;
}
function insert() {
echo "The insert function is called.";
exit;
}
?>
Upvotes: 108
Reputation: 2000
The onclick
attribute in HTML calls JavaScript functions, not PHP functions.
Upvotes: 7
Reputation: 3622
Button clicks are client side whereas PHP is executed server side, but you can achieve this by using Ajax:
$('.button').click(function() {
$.ajax({
type: "POST",
url: "some.php",
data: { name: "John" }
}).done(function( msg ) {
alert( "Data Saved: " + msg );
});
});
In your PHP file:
<?php
function abc($name){
// Your code here
}
?>
Upvotes: 78
Reputation: 2294
You should make the button call the same page and in a PHP section check if the button was pressed:
HTML:
<form action="theSamePage.php" method="post">
<input type="submit" name="someAction" value="GO" />
</form>
PHP:
<?php
if($_SERVER['REQUEST_METHOD'] == "POST" and isset($_POST['someAction']))
{
func();
}
function func()
{
// do stuff
}
?>
Upvotes: 62
Reputation: 41
Use a recursive call where the form action calls itself. Then add PHP code in the same form to catch it. In foo.php
your form will call foo.php
on post
<html>
<body>
<form action="foo.php" method="post">
Once the form has been submitted it will call itself (foo.php
) and you can catch it via the PHP predefined variable $_SERVER
as shown in the code below
<?php
if ($_SERVER['REQUEST_METHOD'] == 'POST') {
echo "caught post";
}
?>
</form>
</body>
</html>
Upvotes: 4
Reputation: 54
Here is an example which you could use:
<html>
<body>
<form action="btnclick.php" method="get">
<input type="submit" name="on" value="on">
<input type="submit" name="off" value="off">
</form>
</body>
</html>
<?php
if(isset($_GET['on'])) {
onFunc();
}
if(isset($_GET['off'])) {
offFunc();
}
function onFunc(){
echo "Button on Clicked";
}
function offFunc(){
echo "Button off clicked";
}
?>
Upvotes: 3
Reputation: 655
Try this:
if($_POST['select'] and $_SERVER['REQUEST_METHOD'] == "POST"){
select();
}
if($_POST['insert'] and $_SERVER['REQUEST_METHOD'] == "POST"){
insert();
}
Upvotes: 10