CODEWITHSUNDEEP
phphtmlformsbutton
Razor
Razor

Reputation: 2641

How to call a PHP function on the click of a button

I have created a page called functioncalling.php that contains two buttons, Submit and Insert.

I want to test which function is executed when a button gets clicked. I want the output to appear on the same page. So, I created two functions, one for each button.

<form action="functioncalling.php">
    <input type="text" name="txt" />
    <input type="submit" name="insert" value="insert" onclick="insert()" />
    <input type="submit" name="select" value="select" onclick="select()" />
</form>

<?php
    function select(){
        echo "The select function is called.";
    }
    function insert(){
        echo "The insert function is called.";
    }
?>

The problem here is that I don't get any output after any of the buttons are clicked.

Where exactly am I going wrong?

Upvotes: 191

Views: 1396869

Answers (13)

Georgi Georgiev
Georgi Georgiev

Reputation: 362

Calling a PHP function using the HTML button: Create an HTML form document which contains the HTML button. When the button is clicked the method POST is called. The POST method describes how to send data to the server. After clicking the button, the array_key_exists() function called.

<?php
    if(array_key_exists('button1', $_POST)) { 
        button1(); 
    } 
    else if(array_key_exists('button2', $_POST)) { 
        button2(); 
    } 
    function button1() { 
        echo "This is Button1 that is selected"; 
    } 
    function button2() { 
        echo "This is Button2 that is selected"; 
    } 
?> 

<form method="post"> 
    <input type="submit" name="button1" class="button" value="Button1" /> 
    <input type="submit" name="button2" class="button" value="Button2" /> 
</form>

source: geeksforgeeks.org

Upvotes: 3

trustidkid
trustidkid

Reputation: 557

You can simply do this. In php, you can determine button click by use of

if(isset($_Post['button_tag_name']){
echo "Button Clicked";
}

Therefore you should modify you code as follows:


<?php

if(isset($_Post['select']){
 echo "select button clicked and select method should be executed";
}
if(isset($_Post['insert']){
 echo "insert button clicked and insert method should be executed";
}
           
        ?>

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html>
    <body>
        <form action="functioncalling.php">
            <input type="text" name="txt" />
            <input type="submit" name="insert" value="insert" onclick="insert()" />
            <input type="submit" name="select" value="select" onclick="select()" />
        </form>

<script>
//This will be processed on the client side
function insert(){
  window.alert("You click insert button");
}

function select(){
  window.alert("You click insert button");
}
</script>
</body>
</html>

Upvotes: 2

M I
M I

Reputation: 3682

You cannot call PHP functions like clicking on a button from HTML. Because HTML is on the client side while PHP runs server side.

Either you need to use some Ajax or do it like as in the code snippet below.

<?php
    if ($_GET) {
        if (isset($_GET['insert'])) {
            insert();
        } elseif (isset($_GET['select'])) {
            select();
        }
    }

    function select()
    {
       echo "The select function is called.";
    }

    function insert()
    {
       echo "The insert function is called.";
    }
?>

You have to post your form data and then check for appropriate button that is clicked.

Upvotes: 20

Sanya Zahid
Sanya Zahid

Reputation: 468

I was stuck in this and I solved it with a hidden field:

<form method="post" action="test.php">
    <input type="hidden" name="ID" value"">
</form>

In value you can add whatever you want to add.

In test.php you can retrieve the value through $_Post[ID].

Upvotes: 5

Vipul Tank
Vipul Tank

Reputation: 109

You can write like this in JavaScript or jQuery Ajax and call the file

$('#btn').click(function(){
  $.ajax({
    url:'test.php?call=true',
    type:'GET',
    success:function(data){
    body.append(data);
    }
  });
})
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.0.1/jquery.min.js"></script>
<form  method='get' >

  <input type="button" id="btn" value="click">
</form>

<?php
    if(isset($_GET['call'])){

        function anyfunction(){
            echo "added";

            // Your funtion code
        }
    }
?>

Upvotes: 8

user5253060
user5253060

Reputation: 141

To show $message in your input:

<?php
    if(isset($_POST['insert'])){
        $message= "The insert function is called.";
    }
    if(isset($_POST['select'])){
        $message="The select function is called.";
    }
?>


<form  method="post">
    <input type="text" name="txt" value="<?php if(isset($message)){ echo $message;}?>" >
    <input type="submit" name="insert" value="insert">
    <input type="submit" name="select" value="select" >
</form>

To use functioncalling.php as an external file you have to include it somehow in your HTML document.

Upvotes: 14

Roopendra
Roopendra

Reputation: 7776

Yes, you need Ajax here. Please refer to the code below for more details.

 

Change your markup like this

<input type="submit" class="button" name="insert" value="insert" />
<input type="submit" class="button" name="select" value="select" />

 

jQuery:

$(document).ready(function(){
    $('.button').click(function(){
        var clickBtnValue = $(this).val();
        var ajaxurl = 'ajax.php',
        data =  {'action': clickBtnValue};
        $.post(ajaxurl, data, function (response) {
            // Response div goes here.
            alert("action performed successfully");
        });
    });
});

In ajax.php

<?php
    if (isset($_POST['action'])) {
        switch ($_POST['action']) {
            case 'insert':
                insert();
                break;
            case 'select':
                select();
                break;
        }
    }

    function select() {
        echo "The select function is called.";
        exit;
    }

    function insert() {
        echo "The insert function is called.";
        exit;
    }
?>

Upvotes: 108

linesarefuzzy
linesarefuzzy

Reputation: 2000

The onclick attribute in HTML calls JavaScript functions, not PHP functions.

Upvotes: 7

Moeed Farooqui
Moeed Farooqui

Reputation: 3622

Button clicks are client side whereas PHP is executed server side, but you can achieve this by using Ajax:

$('.button').click(function() {
  $.ajax({
    type: "POST",
    url: "some.php",
    data: { name: "John" }
  }).done(function( msg ) {
    alert( "Data Saved: " + msg );
  });
});

In your PHP file:

<?php
    function abc($name){
        // Your code here
    }
?>

Upvotes: 78

DavidS
DavidS

Reputation: 2294

You should make the button call the same page and in a PHP section check if the button was pressed:

HTML:

<form action="theSamePage.php" method="post">
    <input type="submit" name="someAction" value="GO" />
</form>

PHP:

<?php
    if($_SERVER['REQUEST_METHOD'] == "POST" and isset($_POST['someAction']))
    {
        func();
    }
    function func()
    {
        // do stuff     
    }
?>

Upvotes: 62

bradleybrentmeyer
bradleybrentmeyer

Reputation: 41

Use a recursive call where the form action calls itself. Then add PHP code in the same form to catch it. In foo.php your form will call foo.php on post

<html>
    <body>
        <form action="foo.php" method="post">

Once the form has been submitted it will call itself (foo.php) and you can catch it via the PHP predefined variable $_SERVER as shown in the code below 

<?php
    if ($_SERVER['REQUEST_METHOD'] == 'POST') {
        echo "caught post";
    }
?>
        </form>
    </body>
</html>

Upvotes: 4

Sagar Mali
Sagar Mali

Reputation: 54

Here is an example which you could use:

<html>
    <body>
        <form action="btnclick.php" method="get">
            <input type="submit" name="on" value="on">
            <input type="submit" name="off" value="off">
        </form>
    </body>
</html>
<?php
    if(isset($_GET['on'])) {
        onFunc();
    }
    if(isset($_GET['off'])) {
        offFunc();
    }

    function onFunc(){
        echo "Button on Clicked";
    }
    function offFunc(){
        echo "Button off clicked";
    }
?>

Upvotes: 3

alexswear
alexswear

Reputation: 655

Try this:

if($_POST['select'] and $_SERVER['REQUEST_METHOD'] == "POST"){
    select();
}
if($_POST['insert'] and $_SERVER['REQUEST_METHOD'] == "POST"){
    insert();
}

Upvotes: 10

Related Questions