CODEWITHSUNDEEP
pythondjango
user1592380
user1592380

Reputation: 36205

Django Url TypeError

when I surf to:

http://127.0.0.1:8000/getEmail/getMyMessages/

I have the following error:

getMyMessages() takes no arguments (1 given)

myapplication/urls.py includes:

urlpatterns = patterns('',
    # Examples:
    url(r'^polls/', include('polls.urls')),
    url(r'^getEmail/', include('get_new_emails.urls')),

I have an app named 'get_new_emails' and get_new_emails/urls.py includes:

urlpatterns = patterns('',
    #url(r'^$', views.index, name='index')
    url(r'getMyMessages', views.getMyMessages)
)

from get_new_emails/views.py:

def getMyMessages():


    from django_mailbox.models import Message

    qs = Message.objects.all()
    count = 0
    for i in qs:
        count += 1
        output = output + str(count)+ " " + i.text +'<br>' + '<br>'

    return HttpResponse(output)

How can I fix this?

Upvotes: 0

Views: 148

Answers (1)

Victor Castillo Torres
Victor Castillo Torres

Reputation: 10811

You forgot the request parameter of your function:

def getMyMessages(request):


    from django_mailbox.models import Message

    qs = Message.objects.all()
    count = 0
    for i in qs:
        count += 1
        output = output + str(count)+ " " + i.text +'<br>' + '<br>'

    return HttpResponse(output)

Upvotes: 1

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