CODEWITHSUNDEEP
phpdatetime
Rodniko
Rodniko

Reputation: 5124

Get hours out of a datetime

Trying to get the hours in 24 hours format from a datetime and nothing works:

$date=date_create("now");
date_add($date,date_interval_create_from_date_string('3 hours'));
$finalDate = date_format($date,"Y-m-d H:i:s");

// $finalDate is "2013-12-25 15:06:45"

Tried the following:

date('H', $finalDate)); // getting 02
date('G', $finalDate)); // getting 02
$finalDate->hours); // getting nothing
date_format($finalDate,"H")); // getting nothing

Read all posts in this site, nothing solved it for me...

Upvotes: 0

Views: 182

Answers (4)

user1467267
user1467267

Reputation:

Please use the newer DateTime object. I also added the out commented variant of how to see the difference between two different DateTime objects.

$date1 = new DateTime('2013-12-15 12:00:00');
$date2 = new DateTime('2013-12-25 13:30:30');

//$interval  = $date1->diff($date2);
//$diff      = $interval->format('%d');
//echo $diff;

echo $date1->format('H');

You can use the PDO variant of $date->add() to write what you did a little cleaner :)

Upvotes: 1

xdazz
xdazz

Reputation: 160863

$date is already an DateTime object.

All you need to do is:

$hour = date_format($date, 'H');

or 

$hour = $date->format('H');

PS: Object oriented style is recommended over Procedural style.

Upvotes: 3

user180100
user180100

Reputation:

With DateTime and "object syntax":

<?php
    $date = new DateTime();
    $date->modify('+3 hours');

    echo $date->format('H');
?>

Upvotes: 2

demonking
demonking

Reputation: 2654

Try this:

$timeStr=strtotime($finalDate); 

echo date('H', $timeStr);

Upvotes: 0

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