CODEWITHSUNDEEP
c
Masoud Mohammadi
Masoud Mohammadi

Reputation: 1749

Printing in Devc

I wrote a simple code with dev but it does not return any thing.but with code block answer shows.what is the problem?

#include <stdio.h>

int main() {
    int x,y,z;
    scanf("%d%d",&x,&y);
    while(z!=0){
        z=x%y;
        printf("%d",z);
    }
    return 0;
}

Upvotes: 1

Views: 129

Answers (4)

haccks
haccks

Reputation: 106112

It invokes undefined behavior because z is used uninitialized. 

while( z!= 0)  
       ^
       |
     z is uninitialized

You may get any thing either expected or unexpected result. Program may crash also. On different compilers you may get different results, which is the case here.

Upvotes: 7

Dipto
Dipto

Reputation: 2738

You are not able to see the output because it is closing the terminal / output window as soon as the program exits.

In code::block, they run a script to hold the output window until you press enter. you can have same effect by using a getch() call at the end, before returning. this will wait for your input and give you a scope to see the result.

Besides, your program has several issues as other answers pointed out. fix them accordingly.

Upvotes: 1

I A Khan
I A Khan

Reputation: 8869

in Your Code you was Assigned z but not initialized z and you are checking while(z!=0) so your code does not return value , fist assigned z to any value for example from scanf.

Upvotes: 1

Digital_Reality
Digital_Reality

Reputation: 4758

Two problems I can see:

1. Value to z is un-assigned. So garbage.
2. Value of z will not change, so it's infinite loop.

Upvotes: 8

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