CODEWITHSUNDEEP
graphontologyrdflib
user1894963
user1894963

Reputation: 665

RDFLib: Remove namespace from a URIRef resource

I have the following resource: http://test.com/domainOnt/email#[email protected]

As in RDFLib, when you search for this in a graph, it returns a URIRef object. I would like to remove the namespace from the object so that it becomes [email protected]

any help is appreciated

Upvotes: 2

Views: 1726

Answers (2)

pedropaulofb
pedropaulofb

Reputation: 11

RDFLib classes have this class hierarchy.

As you can see, a URIRef have the defrag method, here defined.

The part of the URL that you want to get is called 'fragment'. To get it, you can simply do the following:

resource = URIRef('http://test.com/domainOnt/email#[email protected]')
result = resource.fragment

The example provided in RDFLib's documentation to return a URL fragment is the following:

URIRef("http://example.com/some/path/#some-fragment").fragment
>> 'some-fragment'
URIRef("http://example.com/some/path/").fragment
>> ''

Upvotes: 1

Ted Lawless
Ted Lawless

Reputation: 860

URIRef objects in RDFLib are unicode objects and have all of the unicode object methods, like split. The following will work if all of your class names are separated from the namespace with a '#'. 

resource = URIRef('http://test.com/domainOnt/email#[email protected]')
print resource.split('#')[-1]

This question and answer is quite similar to yours.

Upvotes: 3

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