Reputation: 825
Is there a way to replace every "%20" with a space using JavaScript. I know how to replace a single "%20" with a space but how do I replace all of them?
var str = "Passwords%20do%20not%20match";
var replaced = str.replace("%20", " "); // "Passwords do%20not%20match"
Upvotes: 79
Views: 192173
Reputation: 1327
This method uses the decodeURIComponent()
function, which is the most reliable one.
var str = "Passwords%20do%20not%20match%21";
var replaced = decodeURIComponent(str); // "Passwords do not match"
console.log(replaced);
Here are some characters it replaces:
%20 to <space>
%3F to "?"
%21 to "!"
%23 to "#"
etc...
There's a good example of this at the Mozilla docs [https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/decodeURI].
Please note that if you ONLY want to replace "%20", use the replaceAll
function instead:
var str = "Passwords%20do%20not%20match";
var replaced = str.replaceAll("%20", " "); // "Passwords do not match";
console.log(replaced)
Upvotes: 11
Reputation: 4458
using unescape(stringValue)
var str = "Passwords%20do%20not%20match%21";
document.write(unescape(str))
//Output
Passwords do not match!
use decodeURI(stringValue)
var str = "Passwords%20do%20not%20match%21";
document.write(decodeURI(str))
Space = %20
? = %3F
! = %21
# = %23
...etc
Upvotes: 11
Reputation: 4189
If you need to remove white spaces at the end then here is a solution: https://www.geeksforgeeks.org/urlify-given-string-replace-spaces/
const stringQ1 = (string)=>{
//remove white space at the end
const arrString = string.split("")
for(let i = arrString.length -1 ; i>=0 ; i--){
let char = arrString[i];
if(char.indexOf(" ") >=0){
arrString.splice(i,1)
}else{
break;
}
}
let start =0;
let end = arrString.length -1;
//add %20
while(start < end){
if(arrString[start].indexOf(' ') >=0){
arrString[start] ="%20"
}
start++;
}
return arrString.join('');
}
console.log(stringQ1("Mr John Smith "))
Upvotes: -2
Reputation: 2203
Check this out: How to replace all occurrences of a string in JavaScript?
Short answer:
str.replace(/%20/g, " ");
EDIT: In this case you could also do the following:
decodeURI(str)
Upvotes: 173
Reputation: 10148
The percentage %
sign followed by two hexadecimal numbers (UTF-8 character representation) typically denotes a string which has been encoded to be part of a URI. This ensures that characters that would otherwise have special meaning don't interfere. In your case %20
is immediately recognisable as a whitespace character - while not really having any meaning in a URI it is encoded in order to avoid breaking the string into multiple "parts".
Don't get me wrong, regex is the bomb! However any web technology worth caring about will already have tools available in it's library to handle standards like this for you. Why re-invent the wheel...?
var str = 'xPasswords%20do%20not%20match';
console.log( decodeURI(str) ); // "xPasswords do not match"
Javascript has both decodeURI
and decodeURIComponent
which differ slightly in respect to their encodeURI
and encodeURIComponent
counterparts - you should familiarise yourself with the documentation.
Upvotes: 82
Reputation: 108500
Use the global
flag in regexp:
var replaced = str.replace(/%20/g, " ");
^
Upvotes: 14