CODEWITHSUNDEEP
twitter-bootstraplaravel
JeffreyR
JeffreyR

Reputation: 591

laravel link does work but button does not

In laravel i have link called ZOEKEN it goes to 'zoekenindex'. It works

  <li> {{HTML::link('zoekenindex','ZOEKEN')}}</li>

But instead of a a link i want a button:

 <button href="{{ route('zoekenindeze') }}" type="button" class="btn btn-default">Left</button>

this outputs: "Unable to generate a URL for the named route "zoekenindex" as such route does not exist."

I don't get why, because the route works when i use the link code.

Anyone got a idea why this is possible?

Upvotes: 2

Views: 7456

Answers (3)

Harry Bosh
Harry Bosh

Reputation: 3790

Laravel 5

{!! HTML::linkRoute('admin.users.edit', $user->display_name, array($user->id), ['class' => 'btn btn-default']) !!}

Upvotes: 0

elliotanderson
elliotanderson

Reputation: 452

<button href="{{ url('zoekenindeze') }}" type="button" class="btn btn-default">Left</button>

and it will point to the zoekenindeze route

Upvotes: 0

Anam
Anam

Reputation: 12169

Laravel don't find any name route called zoekenindex in your route file.

Create a name route:

Route::get('zoekenindex', array('as' => 'zoekenindex', 'uses' => 'yourController@index'))

Your button: bootstrap by default will create the button. don't worry about the link.

<a href="{{ URL::route('zoekenindex') }}" class="btn btn-default">Left</a>

Laravel helper:

{{ link_to_route('zoekenindex', 'Left', null, array('class' => 'btn btn-default')) }}

or, if you don't like to create a name route, use the following:

<a href="{{ URL::to('zoekenindex') }}" class="btn btn-default">Left</a>

Laravel helper:

{{ link_to('zoekenindex', 'Left', array('class' => 'btn btn-default')) }}

Upvotes: 8

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