CODEWITHSUNDEEP
javajax-wsjava-metro-framework
jesantana
jesantana

Reputation: 1293

Get Url of endpoint using on a handler (JAX-WS)

I am implementing many JAX-WS web services with a common Handler class to validate the correct structure of incoming SOAP messages.

Is there some way to obtain the URL to which is directed the current message so i could get the schema from this url automatically and get the message validated?

Upvotes: 6

Views: 9525

Answers (3)

TueCN
TueCN

Reputation: 11

Neither JAXWSProperties.HTTP_REQUEST_URL nor BindingProvider.ENDPOINT_ADDRESS_PROPERTY worked for me.

This is how i got url in an outbound message on WildFly 10 (Java 7):

public boolean handleMessage(SOAPMessageContext context) {
    String url = (String) context.get(MessageContext.PATH_INFO);
    ...
}

Upvotes: 0

fl4l
fl4l

Reputation: 1640

In my application smc.get(JAXWSProperties.HTTP_REQUEST_URL) returns null. I've fount another way, I hope this helps:

public class HeaderHandler implements SOAPHandler<SOAPMessageContext> {

    public boolean handleMessage(SOAPMessageContext smc) {
        String endpointAddress = (String) smc.get(BindingProvider.ENDPOINT_ADDRESS_PROPERTY);
        log.debug("endpointAddress " +endpointAddress);
    }
}

Upvotes: 10

jesantana
jesantana

Reputation: 1293

Found!!!

public class HeaderHandler implements SOAPHandler<SOAPMessageContext> {

public boolean handleMessage(SOAPMessageContext smc) {
    System.out.println("URL of Endpoint" +smc.get(JAXWSProperties.HTTP_REQUEST_URL));
 }
}

Upvotes: 1

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