CODEWITHSUNDEEP
djangodjango-modelsdjango-admin
greenpau
greenpau

Reputation: 107

Django ModelAdmin and Dropdown Values

in app/models.py:

class Template(models.Model):
    user = models.ForeignKey(User);

in app/admin.py:

class TemplateAdmin(admin.ModelAdmin):
     list_display = ('user', 'status',);

When I edit Template table in Site Adminitration, I get a dropdown for user field. The value in the dropdown is 'username', but app_templates stores the user value as 'user_id'.

How do I make such that the dropdown in Site Adminitration will show combination of first_name, last_name, email instead of 'username'? But, 'templates' table will store the value as 'id'?

Thank you!

Upvotes: 1

Views: 2146

Answers (2)

greenpau
greenpau

Reputation: 107

Change 'user' to:

list_display = ('full_username')

Add the following to class Template:

def full_username(self):
    return str(self.user.first_name) + ' ' + str(self.user.last_name) + ' ' + str(self.user.email);

Upvotes: 0

petkostas
petkostas

Reputation: 7450

From Django Docs:

The unicode (str on Python 3) method of the model will be called to generate string representations of the objects for use in the field’s choices; to provide customized representations, subclass ModelChoiceField and override label_from_instance. This method will receive a model object, and should return a string suitable for representing it.

https://docs.djangoproject.com/en/dev/ref/forms/fields/#modelchoicefield

So to override it:

class UserChoiceField(ModelChoiceField):
    def label_from_instance(self, obj):
        return '%s - %s - %s' % (obj.first_name, obj.last_name, obj.email)

class TemplateAdminForm(forms.ModelForm):
    def __init__(self, *args, **kwargs):
        super(TemplateAdminForm, self).__init__(*args, **kwargs)
        self.fields['user'] = UserChoiceField(queryset=User.objects.all())

class TemplateAdmin(admin.ModelAdmin):
    form = TemplateAdminForm

Upvotes: 1

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