Reputation: 53
I have to sort elements in each row and then display the array.
For example, if the input array is:
5 1 3 1 3 5
INPUT: 7 6 4 OUTPUT: 4 6 7
9 8 2 2 8 9
My code for that was:
for (int i = 0; i < size; i++) { //"size" is the size of the square matrix
for (int j = 0; j < size; j++) {
for (int k = 0; k < size - 1; k++) {
for (int l = 0; l < size - k - 1; l++) {
if (arr[i][j] > arr[i][j+1]) { //arr[][] is of datatype int
int temp = arr[i][j];
arr[i][j] = arr[i][j+1];
arr[i][j+1] = temp;
}
}
}
}
}
Any suggestions?
Upvotes: 0
Views: 227
Reputation: 13483
I would create a method to sort rows, and then just iterate through the rows in the matrix and sort them one at a time. For example:
public static int[] sortRow(int[] row) // selection sort
{
for (int i = 0; i < row.length - 1; i++) {
for (int j = i + 1; j < row.length; j++) {
if (row[i] > row[j]) {
int temp = row[i];
row[i] = row[j];
row[j] = temp;
}
}
}
return row;
}
public static void main(String args[])
{
int[][] arr = {{5, 1, 3}, {7,6,4}, {9,8,2}};
for (int r = 0; r < arr.length; r++) { // for every row in the matrix
arr[r] = sortRow(arr[r]); // set the row to be the sorted row
}
// print out the array to the console
for (int r[] : arr) {
for (int c : r)
System.out.print(c + " ");
System.out.println();
}
}
Output:
1 3 5
4 6 7
2 8 9
Upvotes: 0
Reputation: 1941
for (int i = 0; i < size; i++){ //"size" is the size of the square matrix
for (int j = 0; j < size; j++){
for (int k = j+1; k < size; k++){
if (arr[i][j] > arr[i][k]){ //arr[][] is of datatype int
int temp = arr[i][j];
arr[i][j] = arr[i][k];
arr[i][k] = temp;
}
}
}
}
I don't think you need 4th loop
Upvotes: 5
Reputation: 136002
I would do it simpler
for(int[] r : arr){
Arrays.sort(r);
}
Upvotes: 4