JasonDavis
JasonDavis

Reputation: 48933

Is a global PHP CONSTANT available inside of a Class file?

Is a global PHP CONSTANT available inside of a Class file?

define('SITE_PATH', 'C:/webserver/htdocs/somefolder/');

Then in my class file I try this

public $debug_file = SITE_PATH. 'debug/debug.sql';

This does not seem to work though,

Parse error: parse error, expecting ','' or';'' in C:\webserver\htdocs\somefolder\includes\classes\Database.class.php on line 21

Upvotes: 4

Views: 4268

Answers (4)

Gordon
Gordon

Reputation: 316959

I second what the others said. Since $debugFile seems an optional dependency, I'd suggest to initialize a sane default on creation of the class and then allow changing it by setter injection when needed, e.g.

define('SITE_PATH', 'C:/webserver/htdocs/somefolder/');

class Klass
{
    protected $_debugFile;
    public function __construct()
    {
        $this->_debugFile = SITE_PATH. 'debug/debug.sql' // default
    }
    public function setDebugFile($path)
    {
        $this->_debugFile = $path // custom
    }
}

Note that injecting SITE_PATH, instead of hardcoding it, would be even better practice.

Upvotes: 5

Tyler Carter
Tyler Carter

Reputation: 61557

You cannot have an expression in a class declaration.

I would suggest passing the path in:

public function __construct($path)
{
    $this->debug_path = $path;
}

This gives you more flexibility if you ever want to change the path, you don't have to change a constant, just what you pass in.

Or you could create multiple objects that all have different paths. This is useful if it is an autoloader class, as you might want to have it load multiple directories.

$autoloader = new Autoload(dirname(SYS_PATH));
$autoloader->register_loader();

class Autoload
{
    public $include_path = "";

    public function __construct($include_path="")
    {
        // Set the Include Path
        // TODO: Sanitize Include Path (Remove Trailing Slash)
        if(!empty($include_path))
        {
            $this->include_path = $include_path;
        }
        else
        {
            $this->include_path = get_include_path();
        }

        // Check the directory exists.
        if(!file_exists($this->include_path))
        {
            throw new Exception("Bad Include Path Given");
        }
    }
    // .... more stuff ....
}

Upvotes: 3

Alexey Gopachenko
Alexey Gopachenko

Reputation: 7478

You can't use expression (.) in field initializer. See example one in PHP manual

Upvotes: 2

tanerkay
tanerkay

Reputation: 3930

Yes, however, property values defined at compile time cannot be expressions.

See http://php.net/manual/en/language.oop5.static.php

Upvotes: 0

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