CODEWITHSUNDEEP
javaarrays
Prabu
Prabu

Reputation: 3728

Array replace and added into two arrays using Java

Actual String before the Scrap

Bibliographic data: US6079404 (A) ― 2000-06-27

String h1 = driver.findElement(By.xpath("//*[@id='hedvalue']/h1"))
            .getText().replace("Bibliographic data:", "").trim();

so in h1 got the result for "US6079404 (A) ― 2000-06-27"

my Expected Result:

1.need to store only the value (US6079404 (A) in that h1 String (Note: length Dynamic not a constant) 2.2000-06-27 - how to store this value in another string

Sample o/p

h1 - US6079404 (A1)

h2 - 2000-06-27

Upvotes: 0

Views: 52

Answers (2)

Talha Ahmed Khan
Talha Ahmed Khan

Reputation: 15433

You can use Regular Expression to resolve it. You also don't need to replace the Bibliographic data:.

I suppose that the .getText() gives you 

Bibliographic data:US6079404 (A) ― 2000-06-27

RegEx for that string with groups would be like:

^Bibliographic data:(.*)\s―\s(.*)$

Java Code

String raw = driver.findElement(By.xpath("//*[@id='hedvalue']/h1")).getText();
Pattern pattern = Pattern.compile("^Bibliographic data:(.*)\\s―\\s(.*)$");
Matcher matcher = pattern.matcher(raw);
if(matcher.find()){
    System.out.println(matcher.group(1));
    System.out.println(matcher.group(2));
}

Upvotes: 0

Ted Hopp
Ted Hopp

Reputation: 234795

You can split the string:

String[] parts = driver.findElement(By.xpath("//*[@id='hedvalue']/h1"))
        .getText().replace("Bibliographic data:", "").trim().split(" ― ");
String h1 = parts[0];
String h2 = parts[1];

Upvotes: 3

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