CODEWITHSUNDEEP
c#
Ramesh Rajendran
Ramesh Rajendran

Reputation: 38663

Create dynamic variable name

Can we create dynamic variable in C#?

I know my below code is threw error and very poor coding. But this code have small logic like create dynamic variable 

var name=0;
for(i=0;i<10;i++)// 10 means grid length
{
    name+i=i;
}

var xx1=name1;
var xx2=name2;
var xx3=name3;

Is it possible in c#? Create dynamic variable in c#? and change the variable name in c#? and concatenate the variable name in c#(like we can concatenate any control id or name)...

Why I need the dynamic variable name (scenario):

var variablename=""
var variablename0=No;
var variablename1=Yes;
var variablename2=No;

. . .

I have a gridview with multiple rows. And I need assign server side variable to every row. So I need set of variables in server side. the only I can set Text=<%# variablename+rowCount%> for every template field.

This rowCount means every grid row index.

If the grid has 2 rows, Then rowCount values are 0,1,2

Now I need to change the variablename to variablename0,variablename1,variablename2 dynamically for separate row.

Upvotes: 57

Views: 184960

Answers (5)

Sagar Rawal
Sagar Rawal

Reputation: 1442

This is not possible, it will give you a compile time error,

You can use array for this type of requirement .

For your Reference :

http://msdn.microsoft.com/en-us/library/aa288453%28v=vs.71%29.aspx

Upvotes: 0

Mo Ein
Mo Ein

Reputation: 47

try this one, user json to serialize and deserialize: 

 using System;
    using System.Collections.Generic;
    using System.Linq;
    using System.Text;
    using System.Threading.Tasks;
    using System.Web.Script.Serialization;

    namespace ConsoleApplication1
    {
       public class Program
       {
          static void Main(string[] args)
          {
              object newobj = new object();

              for (int i = 0; i < 10; i++)
              {
                List<int> temp = new List<int>();

                temp.Add(i);
                temp.Add(i + 1);

                 newobj = newobj.AddNewField("item_" + i.ToString(), temp.ToArray());
              }

         }

     }

      public static class DynamicExtention
      {
          public static object AddNewField(this object obj, string key, object value)
          {
              JavaScriptSerializer js = new JavaScriptSerializer();

              string data = js.Serialize(obj);

              string newPrametr = "\"" + key + "\":" + js.Serialize(value);

              if (data.Length == 2)
             {
                 data = data.Insert(1, newPrametr);
              }
            else
              {
                  data = data.Insert(data.Length-1, ","+newPrametr);
              }

              return js.DeserializeObject(data);
          }
      }
   }

Upvotes: 3

Lucifer
Lucifer

Reputation: 1594

Variable names should be known at compile time. If you intend to populate those names dynamically at runtime you could use a List<T>

 var variables = List<Variable>();
 variables.Add(new Variable { Name = inputStr1 });
 variables.Add(new Variable { Name = inputStr2 });

here input string maybe any text or any list

Upvotes: 4

neilcollins
neilcollins

Reputation: 644

C# is strongly typed so you can't create variables dynamically. You could use an array but a better C# way would be to use a Dictionary as follows. More on C# dictionaries here.

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace QuickTest
{
    class Program
    {
        static void Main(string[] args)
        {
            Dictionary<string, int> names = new Dictionary<string,int>();


            for (int i = 0; i < 10; i++)
            {
                names.Add(String.Format("name{0}", i.ToString()), i);
            }

            var xx1 = names["name1"];
            var xx2 = names["name2"];
            var xx3 = names["name3"];
        }
    }
}

Upvotes: 63

gleng
gleng

Reputation: 6304

No. That is not possible. You should use an array instead:

name[i] = i;

In this case, your name+i is name[i].

Upvotes: 17

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