CODEWITHSUNDEEP
pythonexcelcsv
BubbleMonster
BubbleMonster

Reputation: 1416

Parsing CSV files in Python

I have a CSV file that has around 30 headers (columns) and 2000 rows.

HeaderOne | HeaderTwo | HeaderThree
dataRowOne |  dataRowOne | dataRowOne
dataRowTwo |  dataRowTwo | dataRowTwo

I want to use Python to search for a string, then output that row. So say for example I search for 'cocaColaIsTheBest' and it is in cell E2018, I want Python to print out row 2018 with the headers above it.

So far, i've got:

import csv

myExSpreadSheet = csv.reader(open('Simon.csv', 'rb'))

for row in myExSpreadSheet:
    if 'cocaColaIsTheBest' in row:
        print (row)

This prints the row in a dictionary; I want it to print the header as well.

How can I print all headers?

And how can I print specific headers?

Upvotes: 0

Views: 154

Answers (2)

meunierd
meunierd

Reputation: 391

Are you sure you're not better off using a DictReader? Then the headings are associated with their corresponding cells and you can format however you like.

Upvotes: 2

Martijn Pieters
Martijn Pieters

Reputation: 1125368

The headers are the first row; capture those first:

with open('Simon.csv', 'rb') as csvfile:
    myExSpreadSheet = csv.reader(csvfile)
    headers = next(myExSpreadSheet, None)  # grab first row

    for row in myExSpreadSheet:
        if 'cocaColaIsTheBest' in row:
            print headers
            print row

Upvotes: 3

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