TheGeneral
TheGeneral

Reputation: 81573

Replace all non alphanumeric characters, new lines, and multiple white space with one space

I'm looking for a neat regex solution to replace

With a single space


For those playing at home (the following does work)

text.replace(/[^a-z0-9]/gmi, " ").replace(/\s+/g, " ");

My thinking is regex is probably powerful enough to achieve this in one statement. The components I think I'd need are

However, I can't seem to style the regex in the right way (the following doesn't work)

text.replace(/[^a-z0-9]|\s+|\r?\n|\r/gmi, " ");

Input

234&^%,Me,2 2013 1080p x264 5 1 BluRay
S01(*&asd 05
S1E5
1x05
1x5

Desired Output

234 Me 2 2013 1080p x264 5 1 BluRay S01 asd 05 S1E5 1x05 1x5

Upvotes: 206

Views: 233162

Answers (10)

Vaha
Vaha

Reputation: 2607

const processStirng = (str) => (
    str
    .replace(/[^a-z0-9\s]/gi, '') // remove all but alpha-numeric and spaces
    .replace(/ +/g, ' '); // remove duplicated spaces
);
processSting(' $ your    string    here #');

Upvotes: 0

Ryszard Czech
Ryszard Czech

Reputation: 18641

When Unicode comes to play use

text.replace(/[^\p{L}\p{N}]+/gu," ");

EXPLANATION

NODE                     EXPLANATION
--------------------------------------------------------------------------------
  [^\p{L}\p{N}]+           Any character except Unicode letters and digits
                           (1 or more times (matching the most amount possible))

JavaScript code snippet:

const text = `234&^%,Me,2 2013 1080p x264 5 1 BluRąy
S01(*&aśd 05
S1E5
1x05
1x5`
console.log(text.replace(/[^\p{L}\p{N}]+/gu, ` `))

Upvotes: 7

TheGeneral
TheGeneral

Reputation: 81573

Update

Please be aware, the browser landscape changes rapidly, these benchmarks would be woefully out of date, and likely misleading at the time you reading this.


This is an old post of mine, the other answers are good for the most part. However I decided to benchmark each solution and another obvious one (just for fun). I wondered if there was a difference between the regex patterns on different browsers with different sized strings.

So basically I used jsPerf on

  • Testing in Chrome 65.0.3325 / Windows 10 0.0.0
  • Testing in Edge 16.16299.0 / Windows 10 0.0.0

The regex patterns I tested were

  • /[\W_]+/g
  • /[^a-z0-9]+/gi
  • /[^a-zA-Z0-9]+/g

I loaded them up with a string length of random characters

  • length 5000
  • length 1000
  • length 200

Example javascript I used var newstr = str.replace(/[\W_]+/g," ");

Each run consisted of 50 or more sample on each regex, and i run them 5 times on each browser.

Lets race our horses!

Results

                                Chrome                  Edge
Chars   Pattern                 Ops/Sec     Deviation   Op/Sec      Deviation
------------------------------------------------------------------------
5,000   /[\W_]+/g                19,977.80  1.09         10,820.40  1.32
5,000   /[^a-z0-9]+/gi           19,901.60  1.49         10,902.00  1.20
5,000   /[^a-zA-Z0-9]+/g         19,559.40  1.96         10,916.80  1.13
------------------------------------------------------------------------
1,000   /[\W_]+/g                96,239.00  1.65         52,358.80  1.41
1,000   /[^a-z0-9]+/gi           97,584.40  1.18         52,105.00  1.60
1,000   /[^a-zA-Z0-9]+/g         96,965.80  1.10         51,864.60  1.76
------------------------------------------------------------------------
  200   /[\W_]+/g               480,318.60  1.70        261,030.40  1.80
  200   /[^a-z0-9]+/gi          476,177.80  2.01        261,751.60  1.96
  200   /[^a-zA-Z0-9]+/g        486,423.00  0.80        258,774.20  2.15

Truth be known, Regex in both browsers (taking into consideration deviation) were nearly indistinguishable, however i think if it run this even more times the results would become a little more clearer (but not by much).

Theoretical scaling for 1 character

                            Chrome                        Edge
Chars   Pattern             Ops/Sec     Scaled            Op/Sec    Scaled
------------------------------------------------------------------------
5,000   /[\W_]+/g            19,977.80  99,889,000       10,820.40  54,102,000
5,000   /[^a-z0-9]+/gi       19,901.60  99,508,000       10,902.00  54,510,000
5,000   /[^a-zA-Z0-9]+/g     19,559.40  97,797,000       10,916.80  54,584,000
------------------------------------------------------------------------

1,000   /[\W_]+/g            96,239.00  96,239,000       52,358.80  52,358,800
1,000   /[^a-z0-9]+/gi       97,584.40  97,584,400       52,105.00  52,105,000
1,000   /[^a-zA-Z0-9]+/g     96,965.80  96,965,800       51,864.60  51,864,600
------------------------------------------------------------------------

  200   /[\W_]+/g           480,318.60  96,063,720      261,030.40  52,206,080
  200   /[^a-z0-9]+/gi      476,177.80  95,235,560      261,751.60  52,350,320
  200   /[^a-zA-Z0-9]+/g    486,423.00  97,284,600      258,774.20  51,754,840

I wouldn't take to much into these results as this is not really a significant differences, all we can really tell is edge is slower :o . Additionally that i was super bored.

Anyway you can run the benchmark for your self.

Jsperf Benchmark here

Upvotes: 6

egginstone
egginstone

Reputation: 109

For anyone still strugging (like me...) after the above more expert replies, this works in Visual Studio 2019:

outputString = Regex.Replace(inputString, @"\W", "_");

Remember to add

using System.Text.RegularExpressions;

Upvotes: 1

Gregory R.
Gregory R.

Reputation: 1945

To replace with dashes, do the following:

text.replace(/[\W_-]/g,' ');

Upvotes: 3

Dmitri R117
Dmitri R117

Reputation: 2832

A saw a different post that also had diacritical marks, which is great

s.replace(/[^a-zA-Z0-9À-ž\s]/g, "")

Upvotes: 4

Jonny 5
Jonny 5

Reputation: 12389

Be aware, that \W leaves the underscore. A short equivalent for [^a-zA-Z0-9] would be [\W_]

text.replace(/[\W_]+/g," ");

\W is the negation of shorthand \w for [A-Za-z0-9_] word characters (including the underscore)

Example at regex101.com

Upvotes: 349

T-CatSan
T-CatSan

Reputation: 1541

Jonny 5 beat me to it. I was going to suggest using the \W+ without the \s as in text.replace(/\W+/g, " "). This covers white space as well.

Upvotes: 150

Casimir et Hippolyte
Casimir et Hippolyte

Reputation: 89629

Since [^a-z0-9] character class contains all that is not alnum, it contains white characters too!

 text.replace(/[^a-z0-9]+/gi, " ");

Upvotes: 19

Pointy
Pointy

Reputation: 413976

Well I think you just need to add a quantifier to each pattern. Also the carriage-return thing is a little funny:

text.replace(/[^a-z0-9]+|\s+/gmi, " ");

edit The \s thing matches \r and \n too.

Upvotes: 8

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