CODEWITHSUNDEEP
phpregexdatevalidation
LukeP
LukeP

Reputation: 10422

Validate date format in php

I'm trying to validate date using PHP.

I'd like following formats to be valid:

d/m/yy
d/m/yyyy
dd/m/yy
dd/m/yyyy
d/mm/yy
d/mm/yyyy
dd/mm/yy
dd/mm/yyyy

I've tried many regular expressions and different variations of checkdate() function. Currently I have something like this:

function _date_is_valid($str)
{
     if(strlen($str) == 0)
         return TRUE;
     if(substr_count($str,'/') == 2)
     {
         if (preg_match("/^((((31\/(0?[13578]|1[02]))|((29|30)\/(0?[1,3-9]|1[0-2])))\/(1[6-9]|[2-9]\d)?\d{2})|(29\/0?2\/(((1[6-9]|[2-9]\d)?(0[48]|[2468][048]|[13579][26])|((16|[2468][048]|[3579][26])00))))|(0?[1-9]|1\d|2[0-8])\/((0?[1-9])|(1[0-2]))\/((1[6-9]|[2-9]\d)?\d{2}))/", $str))
         {
             $datearray = explode('/',$str);
             if($datearray[2] > 2030)
                 return FALSE;
             return checkdate($datearray[1], $datearray[0], $datearray[2]);
         } 
         else 
         {
             return FALSE;
         }
     }
     return FALSE;
}

This however, validates dates like 11/11/200 and 11/11/200#

How can I validate date to match required format?

Edit: I could check datearray[2] to be between 10 and 30 and 2010 and 2030. But is there a way to check it using regex?

Edit1: return TRUE on strlen($str) == 0 is because I want users to be able to add events without knowing when will the event occur so someone else can qualify the schedule and assign event to certain date later

Just for the record. I ended up doing:

function _date_is_valid($str)
{
    if(strlen($str) == 0) //To accept entries without a date
        return TRUE;
    if(substr_count($str,'/') == 2)
    {
        list($d,$m,$y) = explode('/',$str);
        if(($y >= 10 && $y <= 30) || ($y >= 2010 && $y <= 2030))
        {
            return checkdate($m,$d,$y);
        }
    }
    return FALSE;
}

Thanks for all your answers

Upvotes: 15

Views: 17222

Answers (7)

user1889017
user1889017

Reputation:

an easy way to do this 

<?php
    if(!$formated_date = date_create_from_format('Y-m-d',$dateVar))

Upvotes: 3

Asmarah
Asmarah

Reputation: 134

What I did to validate it was simple

    function dateValidate($pDate) {
    if(empty($pDate)) 
        return true; 
    $chDate = date('Y-m-d', strtotime($pDate));
    if($chDate != '1970-01-01')
        return true;
    else 
        return false;
}

You can find it out with using regexp too

Upvotes: 1

Alix Axel
Alix Axel

Reputation: 154543

function _date_is_valid($str) {
    if (substr_count($str, '/') == 2) {
        list($d, $m, $y) = explode('/', $str);
        return checkdate($m, $d, sprintf('%04u', $y));
    }

    return false;
}

Upvotes: 23

chandoo
chandoo

Reputation: 1316

I have been just changing the martin answer above, which will validate any type of date and return in the format you like.

Just change the format by editing below line of script strftime("10-10-2012", strtotime($dt));

<?php

        echo is_date("13/04/10");

        function is_date( $str )
        {
        $flag = strpos($str, '/');

        if(intval($flag)<=0){
          $stamp = strtotime( $str );
         }else {
          list($d, $m, $y) = explode('/', $str);      
          $stamp = strtotime("$d-$m-$y");
         } 
          //var_dump($stamp) ;

          if (!is_numeric($stamp))
          {
             //echo "ho" ;
             return "not a date" ;       
          }

          $month = date( 'n', $stamp ); // use n to get date in correct format
          $day   = date( 'd', $stamp );
          $year  = date( 'Y', $stamp );

          if (checkdate($month, $day, $year))
          {
             $dt = "$year-$month-$day" ;
             return strftime("%d-%b-%Y", strtotime($dt));
             //return TRUE;
          }else {
          return "not a date" ;
          }
         }

    ?>

Upvotes: 1

ahmetunal
ahmetunal

Reputation: 3950

If it will always will be date / month / year you can use checkdate:

function _date_is_valid($str)
{
    $array = explode('/', $str);

    $day = $array[0];
    $month = $array[1];
    $year = $array[2];

    $isDateValid = checkdate($month, $day, $year);
    return $isDateValid;
}

Upvotes: 8

antpaw
antpaw

Reputation: 15985

how about if(strtotime($str) !== FALSE) $valid = TRUE;

Upvotes: 0

Gumbo
Gumbo

Reputation: 655229

Try this:

function _date_is_valid($str) {
    if (strlen($str) == 0) {
        return TRUE;
    }
    return preg_match('/^(\d{1,2})\/(\d{1,2})\/((?:\d{2}){1,2})$/', $str, $match) && checkdate($match[2], $match[1], $match[3]) && $match[2] <= 2030;
}

Upvotes: 2

Related Questions