CODEWITHSUNDEEP
javajson
user1365697
user1365697

Reputation: 5989

How to convert json in java?

I have this values in cellHashMap

      key = name 
      value = {name ={uri=/book/bookItem3(852)/header}}

I want to get only the 

           book/bookItem3(852)/header

( without the {uri= and the } in the end _

I did this code :

            Map<String, Object> cellHashMap = (HashMap<String, Object>) cell.getValue();
            String cellValue = cellHashMap.get("name").toString(); //$NON-NLS-1$
            String[] splitCell = cellValue.split("uri=/"); //$NON-NLS-1$
            return splitCell[1].substring(0, splitCell[1].length() - 1);

The result of the split are :

  splitCell[0] = {

  splitCell[1] = sbook/bookItem3(852)/header}

it is working but I think it is not the best way to do it

Do you know on better way?

Upvotes: 0

Views: 87

Answers (3)

StoopidDonut
StoopidDonut

Reputation: 8617

My guess is you are not looking to parse JSON since as pointed out, your String isn't a JSON after all. You can however parse this String through normal String manipulation, sample below:

final static String str = "{name ={uri=/book/bookItem3(852)/header}}";

public static void main (String[] args) {

    String value = str.substring((str.indexOf("uri=/") + "uri=/".length()), str.indexOf("}"));
    System.out.println(value);
}

Output:

book/bookItem3(852)/header

Upvotes: 2

Freddy
Freddy

Reputation: 2279

I'm not sure if you have the ability to actually store JSON values in your dictionary, but if you can correct the formatting to actual JSON you can use the JSONObject class to parse the JSON string & retrieve the data.

String jsonstring = "The valid JSON string in your hashmap"
JSONObject json = new JSONObject(jsonstring)
String path = (String) json.get("name");

Again, this method will only work if your hashmap stores valid JSON.

JSONObject Javadoc

Upvotes: 2

tucuxi
tucuxi

Reputation: 17945

This is not JSON (see comments above). If you want to parse what you appear to have (as opposed to what you say you have), you can use the following:

int start = myString.indexOf("uri=");
if (start == -1) { 
    // handle "not found"
}
int end = myString.indexOf("}", start + "uri=".length());
if (end == -1) { 
    // handle "not found"
}
String goal = myString.substring(start + "uri=".length(), end);
// goal = "book/bookItem3(852)/header"

Or a regex:

Matcher m = Pattern.compile("uri=([^}]+)").matcher(myString);
if (m.find()) {
   goal = m.group(1); // "book/bookItem3(852)/header"
} else {
   // handle not found
}

Upvotes: 2

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