CODEWITHSUNDEEP
pythonstringsockets
user3057314
user3057314

Reputation: 85

Python working with hostnames, hostname to IP

In python I need to get IP from hostname:

socket.gethostbyname('www.python.org') # returns ip good
socket.gethostbyname('http://python.org') # raises error

I need to deal with hostnames starting with 'http://' so I figured out a way to remake them like this:

a = 'http://python.org'
a.replace('http://', 'www.')
print a # Why does it print http://python.org ???

I'm not sure I do the right thing. Plz help me with translating this type of hostname to IP

Upvotes: 0

Views: 726

Answers (3)

luk32
luk32

Reputation: 16070

You have several problems.

1st. Error is raised, because http://stuff is not a valid domain. It is natural to expect an error.

2nd. b does not exists in the context you provided.

3rd. It is a dangerous thing to swap http:// for www. blindly. python.org and www.python.org are two different domains and they may point to different places!

You should use regular expressions or some other routines to extract the domain name from an URL, and use gethostbyname on it.

Upvotes: -1

Buddhima Gamlath
Buddhima Gamlath

Reputation: 2328

You should do it like this,

a = 'http://python.org'
a = a.replace('http://', 'www.')  
# a.replace() does not change the original string. it returns a new string (replaced version).
print a

Upvotes: 1

bruno desthuilliers
bruno desthuilliers

Reputation: 77902

You want urlparse:

>>> import urlparse
>>> urlparse.urlparse('http://python.org')
ParseResult(scheme='http', netloc='python.org', path='', params='', query='', fragment='')
>>> urlparse.urlparse('http://python.org').netloc
'python.org'
>>>

Oh, and yes, you don't need to add any "www" in front of the top-level domain.

Upvotes: 7

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