CODEWITHSUNDEEP
javascriptjson
user3020422
user3020422

Reputation: 47

How to iterate through nested json in javascript

I have very complex json created at server side like - 

{"2013": {"11": {"A": 0, "B": 310, "C": 6}, "12": {"A": 0, "B": 281, "C": 5}}, "2014": {"1": {"A": 0, "B": 310, "C": 6}}}

Above JSON object holds the values 'A','B', and 'C' for the three months i.e current + last 2months

var data = {{=monthly_result}}; //Python variable assigned to js var

Now I want to loop through the above object in javascript. Please guide me. Found many links but not any is fully helpful. Thanks in advance!

Upvotes: 0

Views: 4162

Answers (3)

Deepak Ingole
Deepak Ingole

Reputation: 15732

Do something like this

var obj = {"2013": {
            "11": {"A": 0, "B": 310, "C": 6},
            "12": {"A": 0, "B": 281, "C": 5}
            }, 
          "2014": 
            {"1": {"A": 0, "B": 310, "C": 6}
           }
        };

for(outer in obj) {
    for (inner in obj[outer]) {
        for(innermost in obj[item][inner]) {
            alert(outer + "-->" + inner + "-->" + innermost + "-->" + obj[item][inner][innermost]);
        }
    }
}

Upvotes: 0

Yabada
Yabada

Reputation: 1758

To iterate over a "complex" object in a generic way, I would proceed like this :

(psedo code to show how it could be done)

var result = [];
function objIterate(obj, i) {
   result.push([]);
   for (prop in obj){
      if (isObj(prop))
         objIterate(prop, i+1);
      else
         result[i].push(obj[prop]);
   }
}

var obj = yourJson;
objIterate(obj, 0);

Upvotes: 0

OneOfOne
OneOfOne

Reputation: 99205

You can use a for loop, here's a very simple example :

var data = {"2013": {"11": {"A": 0, "B": 310, "C": 6}, "12": 
           {"A": 0, "B": 281, "C": 5}}, "2014": {"1": 
           {"A": 0, "B": 310, "C": 6}}};

for(var year in data) {
    var ydata = data[year];
    for(var num in ydata) {
        var ndata = ydata[num];
        for(var l in ndata) {
            console.log(year + ' -> ' + num + ' -> ' + l + ' = ' + ndata[l]);
        }
    }
}

Upvotes: 1

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