Syntax Correct ,But Error?

Question

I am trying to open a file.Here is the screenshot of what i have done till now:

The first two lines runs error-free but the third or the fourth line(bordered) reports an error even though the statement is syntactically correct and Why does it report "invalid mode" ?

Answer 1

You set the filepath as c:\baby1990.html, but the error says it is c:\x08aby1990.html.

This is because the \b is being interpreted as an escape sequence:

>>> "\b"
'\x08'
>>>

Hence, you need to use a raw-string:

file=open(r"c:\baby1990.html")

Or, more simply, a forwardslash:

file=open("c:/baby1990.html")

Both raw-strings and escape sequences are explained here.