Reputation: 1386
I have a problem with a C program. It was working before I made some changes (from define do var declarations). Now:
gcc m.c -lm -Wall -march=native
So I tried to find a problem using gdb. Now I know more:
Program received signal SIGSEGV, Segmentation fault.
0x0000000000400bbb in GivePeriod (Cx=-0,75, Cy=-0, Iteration_Max=650000,
precision=0,00033329999999999997) at m.c:137
137 orbit[0][0]=0.0;
The problem is in function (which code was not changed), code below.
How can I find the problem?
gcc version 4.8.1 (Ubuntu/Linaro 4.8.1-10ubuntu9)
/*-------------------------------*/
// this function is based on program:
// Program MANCHAOS.BAS
// http://sprott.physics.wisc.edu/chaos/manchaos.bas
// (c) 1997 by J. C. Sprott
//
int GivePeriod(double Cx,double Cy, int Iteration_Max, double precision)
{
double Zx2, Zy2, /* Zx2=Zx*Zx; Zy2=Zy*Zy */
ZPrevieousX,ZPrevieousY,
ZNextX,ZNextY;
int Iteration,
I;
double orbit[Iteration_Max+1][2]; /* array elements are numbered from 0 to length-1 */
/* starting point is critical point */
ZPrevieousX=0.0;
ZPrevieousY=0.0;
orbit[0][0]=0.0;
orbit[0][1]=0.0;
Zx2=ZPrevieousX*ZPrevieousX;
Zy2=ZPrevieousY*ZPrevieousY;
/* iterate and save points for analysis */
for (Iteration=1;Iteration<Iteration_Max+1 ;Iteration++)
{
ZNextY=2*ZPrevieousX*ZPrevieousY + Cy;
ZNextX=Zx2-Zy2 +Cx;
Zx2=ZNextX*ZNextX;
Zy2=ZNextY*ZNextY;
if ((Zx2+Zy2)>ER2) return 0; /* basin of atraction to infinity */
//if (SameComplexValue(ZPrevieousX,ZPrevieousY,ZNextX,ZNextY,precision))
// return 1; /* fixed point , period =1 */
ZPrevieousX=ZNextX;
ZPrevieousY=ZNextY;
/* */
orbit[Iteration][0]=ZNextX;
orbit[Iteration][1]=ZNextY;
};
/* here iteration=IterationMax+1 but last element of orbit has number IterationMax */
for(I=Iteration_Max-1;I>0;I--)
if (SameComplexValue(orbit[Iteration_Max][0],orbit[Iteration_Max] [1],orbit[I][0],orbit[I][1],precision))
return(Iteration_Max-I);
return 0;
}
Upvotes: 3
Views: 1139
Reputation: 11546
Program received signal SIGSEGV, Segmentation fault. 0x0000000000400bbb in GivePeriod (Cx=-0,75, Cy=-0, Iteration_Max=650000, precision=0,00033329999999999997) at m.c:137 137 orbit[0][0]=0.0;
double orbit[Iteration_Max+1][2];
650001 * 2 * 8 (bytes/double) = 10400016
That's probably bigger than your maximum stack size;1 on linux you can check that with ulimit -s
and by default it is 8192 kB.
If you need storage that big, allocate it on the heap with malloc()
and free()
it when done.
1. Memory in a C program is broken into two main areas: the heap, which contains globals and dynamically allocated things (and grows with them), and the small fixed size stack, which is a LIFO structure onto which local data is pushed. Since array orbit
is declared in a function and not allocated dynamically, it is local data and pushed onto the stack. When a function exits, its local data is popped off the stack and discarded.
Upvotes: 7
Reputation: 206727
You're probably blowing your stack. That orbit
array weighs something like 10 megabytes, too much for a stack allocation.
Allocate it on the heap with malloc
or calloc
, and don't forget to free
it on every path that exits your function.
Upvotes: 4