CODEWITHSUNDEEP
javascriptgreasemonkey
user3161533
user3161533

Reputation: 487

simple javascript works in console but not greasemonkey

I'm just trying to submit the already-filled-out login form at this site: http://portal.mypearson.com/mypearson-login.jsp

In firefox console, I can type this: doSubmit(); and it works fine but it doesn't work in greasemonkey. By 'doesn't work' I mean nothing happens. I can do document.forms[0].submit() but the page comes back complaining that the user and pass variables aren't set correctly.

What do I need to do to get the script that works in console to work in greasemonkey?

Upvotes: 0

Views: 242

Answers (1)

ivanspaeth
ivanspaeth

Reputation: 46

Have you tried taking the functionality from the doSubmit() function and performing those actions?

A quick inspection of the code looks like this:

if (!validate(displayForm)) {return false;}
loginForm.loginname.value = displayForm.loginname.value;
loginForm.password.value = hex_md5(displayForm.password.value.toLowerCase());
loginForm.encPassword.value = 'Y';
loginForm.submit();
return true;

It looks like the form is actually just copying its values to another form and then submitting the other form.

You could first start by removing the onsubmit event by using:

displayForm.setAttribute("onsubmit", null)

Or you could just bypass the display form all together and go straight to the source. Your greasemonkey script would look something like this without all the extra steps:

// Setup your authentication values here
var username = "(Your user name)";
var password = "(Your password)";
// Add your variables to the submit form
loginForm.loginname.value = username;
loginForm.password.value = hex_md5(password.toLowerCase());
loginForm.encPassword.value = 'Y'
// submit the form
loginForm.submit();

That will bypass the form that is displayed to the user all together.

Hope that helps.

Upvotes: 1

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