CODEWITHSUNDEEP
shellparameters
user3172764
user3172764

Reputation: 13

Shell Script. Assign $@ or $* to variable

I'm trying to assign all of the parameters to a shell script in the same way that $@ or $* works. Might be easier to explain with an example of what I am trying to do

if [ $# == 0 ]; then
  FIELDS="$($findfields)"
else
  FIELDS=$@
fi
#Show the fields
for field in "$FIELDS"
  do
    echo "$field"
  done

When I run the script with no arguments, a separate script is called and the output is as expected

field1
field2
field3

When I run the script with parameters 

$mysrcipt.sh field1 field2 field3

I get the following

field1 field2 field3

How can I assign $@ to the FIELDS variable so that it works in the same way as the external script?

Many thanks

Upvotes: 1

Views: 163

Answers (1)

fedorqui
fedorqui

Reputation: 289725

To store the values so that they form an array, do:

FIELDS=( "$@" )

Test

$ cat a

if [ $# == 0 ]; then
  FIELDS="$($findfields)"
else
  FIELDS=( "$@" )
fi

#Show the fields
for field in "${FIELDS[@]}"
  do
    echo "$field"
  done

$ ./a a b c
a
b
c

$ ./a "a b c"
a  b c

Upvotes: 1

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