CODEWITHSUNDEEP
phpregexpreg-match-all
Stephani Bishop
Stephani Bishop

Reputation: 1609

preg_match_all Does not return any in the output array

I am trying to parse php variables in a string using regex. For instance, 

$str = '$str1var ="str1"; $str2var = "str2"';

would give me an array ['str1var', 'str2var']

My regex pattern in php is: "/\$(.*?)=/s"

$pattern = "/\$(.*?)=/s";
preg_match_all($pattern, $str, $output_array);

but preg_match_all is returning 0 (no matches) What is wrong with my regex? I tested on a site like http://www.phpliveregex.com/ and it works fine, but my server returns 0;

My Server PHP version is 5.1.6

Upvotes: 3

Views: 564

Answers (3)

manta
manta

Reputation: 1688

 $pattern = '/\$(?P<variable>.*?)(?:\s|)=(?:\s|)"(?P<value>.*?)"/';

Returns an associative array with the value if you need it.

Upvotes: 0

tenub
tenub

Reputation: 3446

Variables are parsed within double quotes in PHP.

Upvotes: 1

jeroen
jeroen

Reputation: 91734

PHP seems to have problem with the double quotes surrounding your pattern, perhaps it is looking for a variable because of the $ sign.

Your code does not work in any php version, but with single quotes it works in all php versions, see the example:

$pattern = '/\$(.*?)=/s';

Upvotes: 3

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