Reputation: 251
This is my code:
Microsoft.CSharp.CSharpCodeProvider provider = new CSharpCodeProvider();
ICodeCompiler compiler = provider.CreateCompiler();
CompilerParameters compilerparams = new CompilerParameters();
compilerparams.GenerateInMemory = false;
CompilerResults results = compiler.CompileAssemblyFromSource(compilerparams, code);
if (results.Errors.HasErrors)
{
StringBuilder errors = new StringBuilder("Compiler Errors :\r\n");
foreach (CompilerError error in results.Errors )
{
errors.AppendFormat("Line {0},{1}\t: {2}\n",
error.Line, error.Column, error.ErrorText);
}
throw new Exception(errors.ToString());
}
else
{
return results.CompiledAssembly;
}
How do I save the created dll to my own specific folder? When I debug, somehow the assembly location is at 'AppData/Local/Temp/' folder.
Upvotes: 2
Views: 7224
Reputation: 147
With OutputAssembly property you can specify just the assembly name. The Assembly will be created in current directory. If you need to specify the full path you have to set the compiler options string in this way:
System.CodeDom.Compiler.CompilerParameters parameters = new CompilerParameters();
parameters.GenerateExecutable = false;
parameters.CompilerOptions = " /out:C:\\Temp\\" + outputAssemblyFile;
Look here, many options can be set in this property. If you set CompilerOptions then OutputAssembly property will be ignored.
I hope this can help.
Upvotes: 3
Reputation: 4883
You could use the OutputAssembly
property of CompilerParameters
to sets the name (path) of the output assembly.
From your example:
...
CompilerParameters compilerparams = new CompilerParameters();
compilerparams.GenerateInMemory = false;
compilerparams.OutputAssembly = "OutputAssembly.dll";
CompilerResults results = compiler.CompileAssemblyFromSource(compilerparams, code);
...
Upvotes: 6