CODEWITHSUNDEEP
pythonsocketsopencv
user3176898
user3176898

Reputation: 31

Trying to send a big file ,python socket

i trying to create a live stream from a webcam to other server . and my problem is the frame i'm geting is to big for the socket to handle
i'm geting this eror :

error: [Errno 10040] A message sent on a datagram socket was larger than the internal message buffer or some other network limit, or the buffer used to receive a datagram into was smaller than the datagram itself

here is my code : 

 import numpy as np
import cv2
import socket
import sys
import select
cap = cv2.VideoCapture(0)
address = ('localhost', 6005)
client_socket=socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
while(True):
    # Capture frame-by-frame
    ret, frame = cap.read()
    print (frame)
    client_socket.connect(('120.0.0.1', 6005))
    client_socket.sendto(frame, address)

i know c and i tought may be i can create a pointer to the frame and send it part by part so my question is how can i cast this method to python and if its possible

Upvotes: 1

Views: 1693

Answers (1)

a.m.
a.m.

Reputation: 2161

From Ans :

Your image is too big to be sent in one UDP packet. You need to split the image data into several packets that are sent individually.

If you don't have a special reason to use UDP you could also use TCP by specifying socket.SOCK_STREAM instead of socket.SOCK_DGRAM. There you don't have to worry about packet sizes and ordering.

You can also look at Ans

Upvotes: 1

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