CODEWITHSUNDEEP
phpmysqlyii
The Humble Rat
The Humble Rat

Reputation: 4696

Yii using a variable with an IN condition

I am trying to pull information into a page using my model. The issue is that I need to use an IN condition on my mysql using a variable.

Here is the code I use currently

$list_id = '1,3';
$clients = ListSubscriber::model()->findAll(array('condition'=>'list_id IN (:list_id)','params'=>array(':list_id'=>$list_id)));

I won't necessarily know how many numbers will be stored within $list_id, hence the need for a variable to work with the IN.

The code does execute without errors, but only seems to return the values for the first number of $list_id, so in this case it only finds users where the list_id = 1.

Any help is appreciated. I have found this question Yii addInCondition However they are using static values, which does not resolve my issue.

When I do use static values, the code executes with results as expected.

Upvotes: 1

Views: 425

Answers (2)

voodoo417
voodoo417

Reputation: 12111

$list_ids = array(1,3);
$clients = ListSubscriber::model()->findAllByAttributes(array('list_id'=>$list_ids));

Upvotes: 2

Kumar V
Kumar V

Reputation: 8830

You can use addInCondition :

$list_id = '1,3';
$criteria = new CDbCriteria();
$arr_list_id = explode(",",$list_id);
$criteria->addInCondition("list_id ", $arr_list_id );
$clients = ListSubscriber::model()->findAll($criteria);

Upvotes: 3

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