CODEWITHSUNDEEP
c#
Craig
Craig

Reputation: 18684

Converting Byte[] to Double

I have a byte[8], which is actually a sequential number. It comes from the RowVersion in a database.

I am really just concerned about the last 4 bytes of the 8 byte array.

I am trying to do this:

 Version = BitConverter.ToDouble(t.Version,4)

'Version' is a double. But, I get an error saying that:

Destination array is not long enough to copy all the items in the collection. Check array index and length.

The value of my 'Version' is:

[0]0 [1]0 [2]0 [3]0 [4]0 [5]0 [6]12 [7]102

What am I doing wrong?

Upvotes: 5

Views: 6758

Answers (2)

MarcinJuraszek
MarcinJuraszek

Reputation: 125610

double requires 8 bytes, so you should get only one from your entire byte[]:

BitConverter.ToDouble(input, 0);

returns

3.7179659497173697E+183

Update

But because you're saying it's a rowversion value, you should convert it to long instead of double:

BitConverter.ToInt64(input, 0);

returns

7353252291589177344

Upvotes: 6

user1968030
user1968030

Reputation:

Use this code:

double[] array= bytearray.Select(i => (double)i).ToArray();

Update:

BitConverter.ToDouble(yournumber, 0);

Upvotes: 0

Related Questions