CODEWITHSUNDEEP
c#.netc#-4.0
Mihai Alin
Mihai Alin

Reputation: 89

C# access image by name

I have multiple images in a C# project and I have to access them randomly. Let's say I have 5 images ( _1, _2, ...) and I generate a random dumber between 1 and 5. How do I access the file correspunding to that number?

pictureBox.Image = Properties.Resources._1

Upvotes: 0

Views: 449

Answers (6)

BRAHIM Kamel
BRAHIM Kamel

Reputation: 13765

Just use something like this 

Random rnd = new Random();
int im = rnd.Next(0, 5);
Image[] images  = new Image[]{Properties.Resources._1,Properties.Resources._2,Properties.Resources._3,Properties.Resources._4,Properties.Resources._5}
pictureBox.Image = images[im];

Upvotes: 1

Deb88
Deb88

Reputation: 1

try this, protected void Page_Load(object sender, EventArgs e) { if (!IsPostBack) { getImage(); } }

private void getImage()
{
    Random rand = new Random();
    int i = rand.Next(1, 6);
    Image1.ImageUrl = "~/image/" + i.ToString() + ".jpg";
    Label1.Text = "image no :" + i.ToString();
}
protected void Button1_Click(object sender, EventArgs e)
{
    getImage();
}

Upvotes: 0

user2819245
user2819245

Reputation:

Assuming, your image resources are named _1, _2, _3, ... Then you could do something like this:

int maxNumberOfImages = ..... the number of images you have
Random rnd = new Random();

pictureBox.Image = Properties.Resources.ResourceManager.GetObject(
    String.Format( "_{0}", rnd.Next(maxNumberOfImages) + 1 )
) as Bitmap;

Upvotes: 2

Selman Genç
Selman Genç

Reputation: 101681

Use this:

//generate your random number
Random rnd = new Random();
string rndNumber = rnd.Next(0,6).ToString();
var myImg = ResourceManager.GetObject(rndNumber) as Bitmap;

If your image file name like _1,_2 etc. then:

string rndNumber = "_" + rnd.Next(0,5).ToString();

Upvotes: 0

Tinwor
Tinwor

Reputation: 7973

You can do something like that:

Random rnd = new Random();
this.pictureBox1.Image = new Bitmap(System.IO.Path.Combine("youFolder",String.Format("_{0}.yourExtension",rnd.Next(0,6)));

For creating random number I have use the Next(min,max) Random's method. Then I simply add a new Image to the pictureBox.

Here you can find a reference of Path.Combine

And here the reference of Random.Next(min,max);

Upvotes: 1

user1968030
user1968030

Reputation:

See this sample:

    Random random= new Random();
    string path=random+".jpeg";
    Image image = Image.FromFile(path);
    pictureBox.Image = image;
    pictureBox.Height = image.Height;
    pictureBox.Width = image.Width;

You can also use:

    Random random= new Random();
    string path=random+".jpeg";
    pictureBox.Image = new Bitmap(path);

Upvotes: 1

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