CODEWITHSUNDEEP
javaspringspring-security
Guillermo81
Guillermo81

Reputation: 189

How to define a pattern in spring security?

I have this 4 pages:

This is the spring security config: 

<security:http auto-config="true" use-expressions="true">
    <security:intercept-url pattern="//pages/project/[ec].*/"     access="hasRole('PROJECT_WRITE')"/>
    <security:intercept-url pattern="/pages/project/load**" access="hasRole('PROJECT_READ')"/>
    <security:intercept-url pattern="/pages/project/detail**" access="hasRole('PROJECT_READ')"/>
</security:http>

I need to filter pages when its starts with e (for edit) and c (for create) but i don't know. This is the correct regex //pages/project/[ec].*/ but don't work.

is it possible?

Load an detail page work fine but is a easy url.

Thanks!

Upvotes: 0

Views: 106

Answers (1)

John R
John R

Reputation: 2096

You have a trailing slash at the end of the regex. You can also remove one of the slashes at the beginning. Try this:

/pages/project/[ec].*

Upvotes: 1

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