CODEWITHSUNDEEP
arraysiteratorziprustrust-0.8
mcandre
mcandre

Reputation: 24642

How do I convert a Zip into an array in rust 0.8?

The docs seem to indicate that after zipping two iterators together, you can turn them into an array with .from_iterator(), but when I try to do this, rust reports:

std::iter::Zip<std::vec::VecIterator<,int>,std::vec::VecIterator<,int>>` does not implement any method in scope named `from_iterator`

Could someone please give working sample code for rust 0.8 that turns a Zip into an array?

Upvotes: 2

Views: 2231

Answers (2)

A.B.
A.B.

Reputation: 16660

Rust 0.8 is dated, you should upgrade to 0.9. The following works in 0.9:

let a = ~[1,12,3,67];
let b = ~[56,74,13,2];
let c: ~[(&int,&int)] = a.iter().zip(b.iter()).collect();
println!("{:?}", c);

Result:

~[(&1, &56), (&12, &74), (&3, &13), (&67, &2)]

Upvotes: 1

Chris Morgan
Chris Morgan

Reputation: 90852

That would be FromIterator::from_iterator(iterator).

The more commonly used interface for that is Iterator.collect (link is to master docs, but it's the same in 0.8 and 0.9), whereby you will call iterator.collect().

Upvotes: 3

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