CODEWITHSUNDEEP
bashcommand-line-arguments
user2612481
user2612481

Reputation: 39

Pass bash variables into subprocess arguments

In a bash shell script I would like to do the following:

for file in /path/to/original/*
  nfcapd -p 12345 -l /path/to/new/file/ -x 'mv %d%f %d/$file'
done

So nfcapd -x lets you add a command to execute on completion. I want to mv %d%f (move directorypath/defaultfilename) to %d/$file (directorypath/original_file_name). Unfortunately, this is saving the new file as "$file" not the value of the $file variable. Is there a way to escape the quotes?

Upvotes: 0

Views: 173

Answers (1)

Jakub Kotowski
Jakub Kotowski

Reputation: 7571

Use double quotes instead of single quotes around the argument to -x, it will be:

nfcapd -p 12345 -l /path/to/new/file/ -x "mv %d%f %d/$file"

Shell variables are not expanded inside single quotes.

Upvotes: 1

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