CODEWITHSUNDEEP
perl
user2896215
user2896215

Reputation: 527

Concatenate scalar with array name

I am trying to concatenate a scalar with array name but not sure how to do. Lets say we have two for loops (one nested inside other) like

for ($i = 0; $i <= 5; $i++) {
    for ($k = 0; $k <=5; $k++) {
       $array[$k] = $k;
    }
}

I want to create 5 arrays with names like @array1, @array2, @array3 etc. The numeric at end of each array represents value of $i when array creation in progress. Is there a way to do it?

Thanks

Upvotes: 1

Views: 379

Answers (2)

Life_Searching_Steps
Life_Searching_Steps

Reputation: 7

You need to add {} and "" to characters, when they are used as variable or array/hash name.

Try this:

for ($i = 0; $i <= 5; $i++){
    for ($k = 0; $k <=5; $k++){
        ${"array$k"}[$k] = $k;
    } 
}
print "array5[4] = $array5[4]
array5[5] = $array5[5]\n";

array5[4] =

array5[5] = 5

Upvotes: 1

TLP
TLP

Reputation: 67900

If you mean to create actual variables, for one thing, its a bad idea, and for another, there is no point. You can simply access a variable without creating or declaring it. Its a bad idea because it is what a hash does, exactly, and with none of the drawbacks.

my %hash;
$hash{array1} = [ 1, 2, 3 ];

There, now you have created an array. To access it, do:

print @{ $hash{array1} };

The hash keys (names) can be created dynamically, just like you want, so it is easy to create 5 different names and assign values to them.

for my $i (0 .. 5) {
    push @{ $hash{"array$i"} }, "foo";
}

Upvotes: 1

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