CODEWITHSUNDEEP
phpdatedatetime
alexus
alexus

Reputation: 7465

Compare given date with today

I have following

$var = "2010-01-21 00:00:00.0"

I'd like to compare this date against today's date (i.e. I'd like to know if this $var is before today or equals today or not)

What function would I need to use?

Upvotes: 250

Views: 555819

Answers (14)

Salman Arshad
Salman Arshad

Reputation: 272106

You can use the DateTime class:

$past   = new DateTime("2010-01-01 00:00:00");
$now    = new DateTime();
$future = new DateTime("2050-01-01 00:00:00");

Comparison operators work [1][2]:

var_dump($past   < $now);     // bool(true)
var_dump($future < $now);     // bool(false)

var_dump($now == $past);      // bool(false)
var_dump($now == clone $now); // bool(true)
var_dump($now == $future);    // bool(false)

var_dump($past   > $now);     // bool(false)
var_dump($future > $now);     // bool(true)

It is also possible to grab the timestamp values from DateTime objects and compare them:

var_dump($past  ->getTimestamp());                        // int(1262286000)
var_dump($now   ->getTimestamp());                        // int(1704067200)
var_dump($future->getTimestamp());                        // int(2524590000)
var_dump($past  ->getTimestamp() < $now->getTimestamp()); // bool(true)
var_dump($future->getTimestamp() > $now->getTimestamp()); // bool(true)

[1] The === operator returns false when comparing two different DateTime objects even when they represent the same date.
[2] When calling new DateTime() repeatedly, the dates will be few microseconds apart and will not match.

Upvotes: 57

Sonu Chohan
Sonu Chohan

Reputation: 273

Try this:

if (date("Y-m-d",strtotime($funding_dt)) >= date("Y-m-d",strtotime('31-01-2007')))
{
    echo "ok";
} else {
    echo "not";
}

Upvotes: 0

Kevin
Kevin

Reputation: 2406

Compare date time objects:

(I picked 10 days - Anything older than 10 days is "OLD", else "NEW")

$now   = new DateTime();
$yourdate = new DateTime("2021-08-24");
$diff=date_diff($yourdate,$now);
$diff_days = $diff->format("%a");
if($diff_days > 10){
    echo "OLD! " . $yourdate->format('m/d/Y');
}else{
    echo "NEW! " . $yourdate->format('m/d/Y');
}

Upvotes: 2

dxvargas
dxvargas

Reputation: 815

Some given answers don't have in consideration the current day!

Here it is my proposal.

$var = "2010-01-21 00:00:00.0"
$given_date = new \DateTime($var);

if ($given_date == new \DateTime('today')) {
  //today
}

if ($given_date < new \DateTime('today')) {
  //past
}

if ($given_date > new \DateTime('today')) {
  //future
}

Upvotes: 3

Bobby Jack
Bobby Jack

Reputation: 16018

That format is perfectly appropriate for a standard string comparison e.g.

if ($date1 > $date2){
  //Action
}

To get today's date in that format, simply use: date("Y-m-d H:i:s").

So:

$today = date("Y-m-d H:i:s");
$date = "2010-01-21 00:00:00";

if ($date < $today) {}

That's the beauty of that format: it orders nicely. Of course, that may be less efficient, depending on your exact circumstances, but it might also be a whole lot more convenient and lead to more maintainable code - we'd need to know more to truly make that judgement call.

For the correct timezone, you can use, for example,

date_default_timezone_set('America/New_York');

Click here to refer to the available PHP Timezones.

Upvotes: 242

Lucas M. Oliveira
Lucas M. Oliveira

Reputation: 69

If you do things with time and dates Carbon is you best friend;

Install the package then:

$theDay = Carbon::make("2010-01-21 00:00:00.0");

$theDay->isToday();
$theDay->isPast();
$theDay->isFuture();
if($theDay->lt(Carbon::today()) || $theDay->gt(Carbon::today()))

lt = less than, gt = greater than

As in the question:

$theDay->gt(Carbon::today()) ? true : false;

and much more;

Upvotes: 0

enceladus
enceladus

Reputation: 91

Expanding on Josua's answer from w3schools:

//create objects for the dates to compare
$date1=date_create($someDate);
$date2=date_create(date("Y-m-d"));
$diff=date_diff($date1,$date2);
//now convert the $diff object to type integer
$intDiff = $diff->format("%R%a");
$intDiff = intval($intDiff);
//now compare the two dates
if ($intDiff > 0)  {echo '$date1 is in the past';}
else {echo 'date1 is today or in the future';}

I hope this helps. My first post on stackoverflow!

Upvotes: 4

Nelu Bidonelu
Nelu Bidonelu

Reputation: 315

Few years later, I second Bobby Jack's observation that last 24 hrs is not today!!! And I am surprised that the answer was so much upvoted...

To compare if a certain date is less, equal or greater than another, first you need to turn them "down" to beginning of the day. In other words, make sure that you're talking about same 00:00:00 time in both dates. This can be simply and elegantly done as:

strtotime("today") <=> strtotime($var)

if $var has the time part on 00:00:00 like the OP specified.

Replace <=> with whatever you need (or keep it like this in php 7)

Also, obviously, we're talking about same timezone for both. For list of supported TimeZones

Upvotes: 6

Richard de Ree
Richard de Ree

Reputation: 2540

$date1=date_create("2014-07-02");
$date2=date_create("2013-12-12");
$diff=date_diff($date1,$date2);

(the w3schools example, it works perfect)

Upvotes: 5

Lynnell Neri
Lynnell Neri

Reputation: 483

One caution based on my experience, if your purpose only involves date then be careful to include the timestamp. For example, say today is "2016-11-09". Comparison involving timestamp will nullify the logic here. Example,

//  input
$var = "2016-11-09 00:00:00.0";

//  check if date is today or in the future
if ( time() <= strtotime($var) ) 
{
    //  This seems right, but if it's ONLY date you are after
    //  then the code might treat $var as past depending on
    //  the time.
}

The code above seems right, but if it's ONLY the date you want to compare, then, the above code is not the right logic. Why? Because, time() and strtotime() will provide include timestamp. That is, even though both dates fall on the same day, but difference in time will matter. Consider the example below:

//  plain date string
$input = "2016-11-09";

Because the input is plain date string, using strtotime() on $input will assume that it's the midnight of 2016-11-09. So, running time() anytime after midnight will always treat $input as past, even though they are on the same day.

To fix this, you can simply code, like this:

if (date("Y-m-d") <= $input)
{
    echo "Input date is equal to or greater than today.";
}

Upvotes: 6

Hassan
Hassan

Reputation: 155

$toBeComparedDate = '2014-08-12';
$today = (new DateTime())->format('Y-m-d'); //use format whatever you are using
$expiry = (new DateTime($toBeComparedDate))->format('Y-m-d');

var_dump(strtotime($today) > strtotime($expiry)); //false or true

Upvotes: 12

kamakazuu
kamakazuu

Reputation: 471

To complete BoBby Jack, the use of DateTime OBject, if you have php 5.2.2+ :

if(new DateTime() > new DateTime($var)){
    // $var is before today so use it

}

Upvotes: 47

Alix Axel
Alix Axel

Reputation: 154553

Here you go:

function isToday($time) // midnight second
{
    return (strtotime($time) === strtotime('today'));
}

isToday('2010-01-22 00:00:00.0'); // true

Also, some more helper functions:

function isPast($time)
{
    return (strtotime($time) < time());
}

function isFuture($time)
{
    return (strtotime($time) > time());
}

Upvotes: 62

Tyler Carter
Tyler Carter

Reputation: 61567

strtotime($var);

Turns it into a time value

time() - strtotime($var);

Gives you the seconds since $var

if((time()-(60*60*24)) < strtotime($var))

Will check if $var has been within the last day.

Upvotes: 314

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