Reputation: 7043
While trying to compile a proto file named UserOptions.proto which has an import named Account.proto using the below command
protoc --proto_path=/home/project_new1/account --java_out=/home/project_new1/source /home/project_new1/settings/Useroptions.proto
I get the following error :
/home/project_new1/settings/UserOptions.proto: File does not reside within any path specified using --proto_path (or -I). You must specify a --proto_path which encompasses this file.
PS: UserOptions.proto present in the directory /home/project_new1/settings
imports Account.proto present in the directory
/home/project_new1/account
Proto descriptor files:
UserOptions.proto
package settings;
import "Account.proto";
option java_outer_classname = "UserOptionsVOProto";
Account.proto
package account;
option java_outer_classname = "AccountVOProto";
message Object
{
optional string userId = 1;
optional string service = 2;
}
Upvotes: 20
Views: 60774
Reputation: 161
For my environment, Windows 10 Pro operating system and C++ programming languaje, I used the protoc-3.12.2-win64.zip that you can downloat it from here. You should open a Windows PowerShell inside the protoc-3.12.2-win64\bin path and then you must execute one of the next commands:
.\protoc.exe -I=C:\Users\UserName\Desktop\SRC --cpp_out=C:\Users\UserName\Desktop\DST C:\Users\UserName\Desktop\SRC\addressbook.proto
Or
.\protoc.exe --proto_path=C:\Users\UserName\Desktop\SRC --cpp_out=C:\Users\UserName\Desktop\DST C:\Users\UserName\Desktop\SRC\addressbook.proto
Note:
1- My source folder is in: C:\Users\UserName\Desktop\SRC
2- My destination folder is in: C:\Users\UserName\Desktop\DST
3- My .proto file is in: C:\Users\UserName\Desktop\SRC\addressbook.proto
Upvotes: 0
Reputation: 45296
As the error message states, the file you pass on the command line needs to be in one of the --proto_path
s. In your case, you have only specified one --proto_path
of:
/home/project_new1/
But the file you're passing is:
/home/project_new1/settings/UserOptions.proto
Notice that the file is not in the account
subdirectory; it's in settings
instead.
You have two options:
--proto_path
argument to add .../settings
to the path.(Recommended) Use the root of your source tree as the proto path. E.g.:
protoc --proto_path=/home/project_new1/ --java_out=/home/project_new1 /home/project_new1/settings/UserOptions.proto
In this case, to import Account.proto
, you'll need to write:
import "account/Account.proto";
Upvotes: 32
Reputation: 424
For those of us who want this really spelled out, here is an example where I have installed the protoc beta for gRPC using NuGet Packages Google.Protobuf, Grpc.Core and Grpc.Tools. My solution packages are one level above my Grpc directory (i.e. at BruTrader\packages). My .proto files are at BruTrader\Grpc\protos.
1. My .proto file:
syntax = "proto3";
import "timestamp.proto";
import "enums.proto";
package BruTrader.Grpc;
message DividendMessage {
double amount = 1;
google.protobuf.Timestamp dateUnix = 2;
}
2. my GenerateProto.bat file:
..\packages\Google.Protobuf.3.0.0-beta2\tools\protoc.exe -I..\Grpc\protos -I..\packages\Google.Protobuf.3.0.0-beta2\tools\google\protobuf --csharp_out=..\Grpc\Generated --grpc_out=..\Grpc\Generated --plugin=protoc-gen-grpc=..\packages\Grpc.Tools.0.13.0\tools\grpc_csharp_plugin.exe %1
3. my BuildProtos.bat
call GenerateProto ..\Grpc\protos\masterinstrument.proto
call GenerateProto .\protos\instrument.proto
etc.
4. BuildProtos.bat is executed as a Pre-build event on my Grpc project like this:
CD $(ProjectDir)
CALL "$(ProjectDir)BuildProtos.bat"
Upvotes: 3