CODEWITHSUNDEEP
javaxmlxpathjoox
Jakub Kubrynski
Jakub Kubrynski

Reputation: 14149

Returning first level tag in JOOX

I've following xml:

<project xmlns="http://maven.apache.org/POM/4.0.0"
         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
  <modelVersion>4.0.0</modelVersion>

  <groupId>com.sndbox</groupId>
  <artifactId>joox-test</artifactId>
  <version>1.0.0</version>

  <dependencies>
    <dependency>
      <groupId>org.jooq</groupId>
      <artifactId>joox</artifactId>
      <version>1.2.0</version>
    </dependency>
    <dependency>
      <groupId>com.google.guava</groupId>
      <artifactId>guava</artifactId>
      <version>15.0</version>
    </dependency>
  </dependencies>

</project>

Now I want to find version tag, but only on the root level of the document (project version = 1.0.0). When i use find("version") it works like xpath("//version") and returns tags from whole document, and I need equivalent of the xpath("version") method.

Any ideas?

Upvotes: 2

Views: 182

Answers (1)

Lukas Eder
Lukas Eder

Reputation: 221125

You have a couple of options to fetch the /project/version tag:

$(doc).xpath("/project/version");
$(doc).child("version"); // matches the first
$(doc).children("version"); // matches all

Upvotes: 2

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