CODEWITHSUNDEEP
sql
josef_skywalker
josef_skywalker

Reputation: 1107

Select rows with same id but different value in another column

I tried for hours and read many posts but I still can't figure out how to handle this request:

I have a table like this:

+------+------+
|ARIDNR|LIEFNR|
+------+------+
|1     |A     |
+------+------+
|2     |A     |
+------+------+
|3     |A     |
+------+------+
|1     |B     |
+------+------+
|2     |B     |
+------+------+

I would like to select the ARIDNR that occurs more than once with the different LIEFNR.

The output should be something like:

+------+------+
|ARIDNR|LIEFNR|
+------+------+
|1     |A     |
+------+------+
|1     |B     |
+------+------+
|2     |A     |
+------+------+
|2     |B     |
+------+------+

Upvotes: 88

Views: 504262

Answers (8)

Madhur Sodhi
Madhur Sodhi

Reputation: 121

Select A.ARIDNR,A.LIEFNR
from Table A
join Table B
on A.ARIDNR = B.ARIDNR
and A.LIEFNR<> B.LIEFNR
group by A.ARIDNR,A.LIEFNR

Upvotes: 1

Hasan Shouman
Hasan Shouman

Reputation: 2362

Try this please. I checked it and it's working:

SELECT *
FROM Table
WHERE ARIDNR IN (
    SELECT ARIDNR
    FROM Table
    GROUP BY ARIDNR
    HAVING COUNT(distinct LIEFNR) > 1
)

Upvotes: 121

Thys
Thys

Reputation: 121

This is an old question yet I find that I also need a solution for this from time to time. The previous answers are all good and works well, I just personally prefer using CTE, for example:

DECLARE @T TABLE (ARIDNR INT, LIEFNR varchar(5)) --table variable for loading sample data
INSERT INTO @T (ARIDNR, LIEFNR) VALUES (1,'A'),(2,'A'),(3,'A'),(1,'B'),(2,'B'); --add your sample data to it
WITH duplicates AS --the CTE portion to find the duplicates
(
    SELECT ARIDNR FROM @T GROUP BY ARIDNR HAVING COUNT(*) > 1
)
SELECT t.* FROM @T t --shows results from main table
INNER JOIN duplicates d on t.ARIDNR = d.ARIDNR --where the main table can be joined to the duplicates CTE

Yields the following results:

1|A
1|B
2|B
2|A

Upvotes: 1

ranojan
ranojan

Reputation: 837

$sql="SELECT * FROM TABLE_NAME WHERE item_id=".$item_id;

$query=mysql_query($sql);

while($myrow=mysql_fetch_array($query)) {

echo   print_r($myrow,1);


}

Upvotes: -3

Tejas Patel
Tejas Patel

Reputation: 89

You can simply achieve it by

SELECT *
FROM test
WHERE ARIDNR IN
    (SELECT ARIDNR FROM test
     GROUP BY ARIDNR
     HAVING COUNT(*) > 1)
GROUP BY ARIDNR, LIEFNR;

Thanks.

Upvotes: 0

MANIVANNAN
MANIVANNAN

Reputation: 1

Use this

select * from (
 SELECT ARIDNR,LIEFNR,row_number() over 
     (partition by ARIDNR order by ARIDNR) as RowNum) a
where a.RowNum >1

Upvotes: 0

Segfault
Segfault

Reputation: 8290

Join the same table back to itself. Use an inner join so that rows that don't match are discarded. In the joined set, there will be rows that have a matching ARIDNR in another row in the table with a different LIEFNR. Allow those ARIDNR to appear in the final set.

SELECT * FROM YourTable WHERE ARIDNR IN (
    SELECT a.ARIDNR FROM YourTable a
    JOIN YourTable b on b.ARIDNR = a.ARIDNR AND b.LIEFNR <> a.LIEFNR
)

Upvotes: 13

Yuck
Yuck

Reputation: 50825

This ought to do it:

SELECT *
FROM YourTable
WHERE ARIDNR IN (
    SELECT ARIDNR
    FROM YourTable
    GROUP BY ARIDNR
    HAVING COUNT(*) > 1
)

The idea is to use the inner query to identify the records which have a ARIDNR value that occurs 1+ times in the data, then get all columns from the same table based on that set of values.

Upvotes: 82

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