Reputation: 12747
I have a data set that includes a whole bunch of data about students, including their current school, zipcode of former residence, and a score:
students <- read.table(text = "zip school score
43050 'Hunter' 202.72974236
48227 'NYU' 338.49571519
48227 'NYU' 223.48658339
32566 'CCNY' 310.40666224
78596 'Columbia' 821.59318662
78045 'Columbia' 853.09842034
60651 'Lang' 277.48624384
32566 'Lang' 315.49753763
32566 'Lang' 80.296556533
94941 'LIU' 373.53839238
",header = TRUE,sep = "")
I want a heap of summary data about it, per school. How many students from each school are in the data set, how many unique zipcodes per school, average and cumulative score. I know I can get this by using tapply
to create a bunch of tmp
frames:
tmp.mean <- data.frame(tapply(students$score, students$school, mean))
tmp.sum <- data.frame(tapply(students$score, students$school, sum))
tmp.unique.zip <- data.frame(tapply(students$zip, students$school, function(x) length(unique(x))))
tmp.count <- data.frame(tapply(students$zip, students$school, function(x) length(x)))
Giving them better column names:
colnames(tmp.unique.zip) <- c("Unique zips")
colnames(tmp.count) <- c("Count")
colnames(tmp.mean) <- c("Mean Score")
colnames(tmp.sum) <- c("Total Score")
And using cbind
to tie them all back together again:
school.stats <- cbind(tmp.mean, tmp.sum, tmp.unique.zip, tmp.count)
I think the cleaner way to do this is:
library(plyr)
school.stats <- ddply(students, .(school), summarise,
record.count=length(score),
unique.r.zips=length(unique(zip)),
mean.dist=mean(score),
total.dist=sum(score)
)
The resulting data looks about the same (actually, the ddply
approach is cleaner and includes the schools as a column instead of as row names). Two questions: is there better way to find out how many records there are associated with each school? And, am I using ddply
efficiently here? I'm new to it.
Upvotes: 2
Views: 170
Reputation: 8691
If performance is an issue, you can also use data.table
require(data.table)
tab_s<-data.table(students)
setkey(tab_s,school)
tab_s[,list(total=sum(score),
avg=mean(score),
unique.zips=length(unique(zip)),
records=length(score)),
by="school"]
school total avg unique.zips records
1: Hunter 202.7297 202.7297 1 1
2: NYU 561.9823 280.9911 1 2
3: CCNY 310.4067 310.4067 1 1
4: Columbia 1674.6916 837.3458 2 2
5: Lang 673.2803 224.4268 2 3
6: LIU 373.5384 373.5384 1 1
Upvotes: 3