Reputation: 2455
Remove strings with numbers and special characters using regular expression.Here is my code
var string = "[Account0].&[1]+[Account1].&[2]+[Account2].&[3]+[Account3].&[4]";
var numbers = string.match(/(\d+)/gi);
alert(numbers.join(','));
here output is : 0,1,1,2,2,3,3,4
But i want the following output 1,2,3,4
Can any one please help me.
Thanks,
Upvotes: 0
Views: 565
Reputation: 785196
You can do:
string = "[Account0].&[1]+[Account1].&[2]+[Account2].&[3]+[Account3].&[4]";
repl = string.replace(/.*?\[(\d+)\][^\[]*/g, function($0, $1) { return $1 });
//=> "1234"
Upvotes: 1
Reputation: 8332
I guess the simplest solution in this case would be:
\[(\d+)\]
simply saying that you only want the digits enclosed by brackets.
Regards
Upvotes: 0
Reputation: 5340
Seemd what you want is [\d+], use exec like this,
var myRe = /\[(\d+)\]/gi;
var myArray, numbers = [];
while ((myArray = myRe.exec(string)) !== null) {
numbers.push(myArray[1]);
}
Upvotes: 2