CODEWITHSUNDEEP
python
Goku
Goku

Reputation: 1840

Pythonic way to unpack a inner string and process it

I want to split a inner string in order to get every item, the string is into a [()] structure,the object to process could be something like:

[(u'|name1|name2|name3|123|124|065|',)]

or

[(u'|name1|',)]

or 

[(u'')]

or even

false

To get the items from the string I only need:

mystring.split('|')

But I think that my final approach is ugly and error-prone:

mylist[0][0].split('|')

How can I get a items list in a clean and pythonic way?

Upvotes: 0

Views: 86

Answers (3)

Hernán Acosta
Hernán Acosta

Reputation: 695

I think your approach is correct.

But what about the first and last elements of split('|') result?. They are empty because your strings starts and ends with a '|'.

You could use list comprehension.

[name for name in mylist[0][0].split('|') if name]

Or striping the string before:

   mylist[0][0].strip('|').split('|')

Upvotes: 1

colcarroll
colcarroll

Reputation: 3682

I agree that you're getting the best you can, but if you just want a different (equivalent) way of doing it,

from operator import itemgetter
f = itemgetter(0)
f(f(mylist)).split('|')

Upvotes: 1

bgusach
bgusach

Reputation: 15165

Just do some previous checking.

If the string can be nested at not constant depth, just wrap the extraction in a loop until it is instance of basestring.

def split(container):
    if not container:
        return []

    return container[0][0].split('|')

Upvotes: 1

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